COM: matlabObj.Feval() - works for calling one function, how would it work for calling a nested set of functions?

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Take this c# / .NET example of calling a Feval on "cov" for variable t2, which works great:
> t2.GetType()
[System.Double[,]]
> object results = null; matlab.Feval("cov", 1, out results, t2)
> results
object[1] { double[10, 10] { { 32.2, -34.599999999999994, 71.65, 1856.1999999999998, 94.25, 35.45, 92.2, 152.3, -138.3, 157 }, { -34.599999999999994, 2939.7999999999993, 2205.55, 18073.399999999998, -40.24999999999994, 261.15000000000003, 2120.3999999999996, 69.10000000000008, 1741.9, 3924 }, { 71.65, 2205.55, 3813.3, 15569.649999999998, 728.5, 39.14999999999998, 3730.3999999999996, 1317.1, 1380.65, 6561.5 }, { 1856.1999999999998, 18073.399999999998, 15569.649999999998, 395910.19999999995, 7004.25, 6084.450000000001, 17791.2, 13353.3, -6674.299999999999, 34322 }, { 94.25, -40.24999999999994, 728.5, 7004.25, 432.5, 61.750000000000014, 788, 729.5000000000001, -400.75, 1367.5 }, { 35.45, 261.15000000000003, 39.14999999999998, 6084.450000000001, 61.750000000000014, 123.2, 79.19999999999999, 119.8, -135.04999999999998, 189.5 }, { 92.2, 2120.3999999999996, 3730.3999999999996, 17791.2, 788, 79.19999999999999, 3677.2, 1419.8000000000002, 1159.2, 6482 }, { 152.3, 69.10000000000008, 1317.1, 13353.3, 729.5000000000001, ...
This is equivalent to calling:
cov(t2)
How would you call in c# the matlab equivalent of:
cov(cov(t2)) % ?
Obviously, something like this:
> object results = null; matlab.Feval("cov(cov)", 1, out results, t2)
System.Runtime.InteropServices.COMException: Undefined function 'cov(cov)' for input arguments of type 'double'.
+ System.RuntimeType.ForwardCallToInvokeMember(string, System.Reflection.BindingFlags, object, object[], bool[], int[], System.Type[], System.Type)
+ MLApp.MLAppClass.Feval(string, int, out object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object, object)
>
fails ... what would the syntax be to call this?
Not using .Execute or .Eval on purpose, as calling a function is way better (data does not get publicly available within the global environment, and parallelization is possible within a c# multi-threaded execution environment.

Answers (1)

Vatsal
Vatsal on 7 May 2024
Hi Andy,
To "call cov(cov(t2))" from C# using the "Feval" method, it is necessary to approach this in two steps due to "Feval" being able to call only one MATLAB function at a time. Initially, execute the inner 'cov' function and then use its output as the input for the outer 'cov' function.
Here is how you can do it:
  1. Call the 'cov' function on t2 and store the result.
  2. Call the 'cov' function again, but this time on the result from step 1.
Here is an example in C#:
// Call the inner function
object innerResult = null;
matlab.Feval("cov", 1, out innerResult, t2);
// Call the outer function using the result of the inner function
object outerResult = null;
matlab.Feval("cov", 1, out outerResult, innerResult);
I hope this helps!

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