How does this code solve the problem of incorrectly using vertcat to concatenate arrays with inconsistent dimensions?

2 views (last 30 days)
clear;
clc;
w1=1;
l1=0.125;
l3=0.600;
l4=0.150;
l6=0.275;
l61=0.575;
for m=1:3601
o1(m)=pi*(m-1)/1800;
o31(m)=atan((l6+l1*sin(o1(m)))/(l1*cos(o1(m))));
if o31(m)>=0
o3(m)=o31(m);
else o3(m)=pi+o31(m);
end
s3(m)=(l1*cos(o1(m)))/cos(o3(m));
o4(m)=pi-asin((l61-13*sin(o3(m)))/14);
se(m)=13*cos(o3(m))+14*cos(o4(m));
if o1(m)==pi/2
o3(m)=pi/2;
s3(m)=l1+16;
end
if o1(m)==3*pi/2
o3(m)=pi/2;
s3(m)=l6-l1;
end
A1=[cos(o3(m)),-s3(m)*sin(o3(m)),0,0;sin(o3(m)),s3(m)*cos(o3(m)),0,0;0,-l3*sin(o3(m)),-l4*sin(o4(m)),-1;0,l3*cos(o3(m)),l4*cos(o4(m)),0];
B1=w1*[-l1*sin(o1(m));l1*cos(o1(m));0;0];
D1=A1\B1;
E1(:,m)=D1;
ds(m)=D1(1);
w3(m)=D1(2);
w4(m)=D1(3);
ve(m)=D1(4);
A2=[cos(o3(m)),-s3(m)*sin(o3(m)),0,0;sin(o3(m)),s3(m)*cos(o3(m)),0,0;0,-l3*sin(o3(m)),-l4*sin(o4(m)),-1;0,l3*cos(o3(m)),l4*cos(o4(m)),0];
B2=-[-w3(m)*sin(o3(m)),(-ds(m)*sin(o3(m))-s3(m)*w3(m)*cos(o3(m))),0,0;w3(m)*cos(o3(m)),(ds(m)*cos(o3(m))-s3(m)*w3(m)*sin(o3(m))),0,0;0,-l3*w3(m)*cos(o3(m)),-l4*w4(m)*cos(o4(m)),0;0,-l3*w3(m)*sin(o3(m)),-l4*w4(m)*sin(o4(m)),0]*[ds(m);w3(m);w4(m);ve(m)];
C2=w1*[-l1*w1*cos(o1(m));-l1*w1*sin(o1(m));0;0];
B=B2+C2;
D2=A2\B;
E2(:,m)=D2;
dds(m)=D2(1);
a3(m)=D2(2);
a4(m)=D2(3);
ae(m)=D2(4);
end
o11=o1*180/pi;
y=[o3*180/pi;
04*180/pi];
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
w=[w3;w4];
a=[a3;a4];figure;
subplot(221);
h1=yyaxis(o11,y,o11, se);
axis equal;
title('位置线图');
xlabel('\it\thetal');
ylabel('\it\theta3,\theta4,Se');
subplot(222);
h2=yyaxis(o11,w,o11,ve);
title('速度线图');
xlabel('\it\theta1');
ylabel('\it\omega3,\omega4,Ve');
subplot(212);
h3=yyaxis(o11,a,o11,ae);
title('加速度线图');
xlabel('\it\theta1');
ylabel('\it\alpha3,\alpha4,\alphaE');
F=[o11;o3./pi*180;o4./pi*180;se;w3;w4;ve;a3;a4;ae]';
G=F(1:100:3601,:);

Accepted Answer

Voss
Voss on 7 Jun 2024
On the line that throws the error you have:
y=[o3*180/pi;
04*180/pi];
where o3 is of size 1x3601 and 04 is a scalar (the scalar number 4). I suspect you meant to use o4, which is the same size as o3.
y=[o3*180/pi;
o4*180/pi];

More Answers (0)

Categories

Find more on Performance and Memory in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!