Finding if numbers are within range

Hello, just trying to figure out a way to find a number in a vector within range. I'm trying practice for loops but still bad at it.

%the range is from 1 to 10

xRange = [5 2 1 -1 5 67 3]

for inside = xRange(1,1):length(xRange)
if xInside, out of range
delete number
else
store number in new vector/keep it in the same vector
end

I tried doing something like

if xInside == 0 xInside(xInside==0) = []; %which sould delete the 0

end

but what if 0 was part of it?

so i tried it in nan

if xInside < max(xRange) | xInside > min(xRange)

turn the number into NaN. end

but not sure how to get that last part.

Answer 1

[Andrei Bobrov]

r = [1, 10];
xRange = [5 2 1 -1 5 67 3];

ii = xRange >= r(1) & xRange <= r(2)
out = xRange;
out(~ii) = nan;

Answer 2

[Ingrid]

I do not think you need to use a for loop for this problem, instead using a vectorized solution is much faster and easier to read

belowRange = (xRange < 1);
aboveRange = (xRange > 10);

iRemove = or(belowRange,aboveRange);
xRange(iRemove) = [];

should do the trick

Answer 3

[Rushikesh Tade]

input_vector=1:100;
range_upper_limit=50;
range_lower_limit=25;

indices_in_input_vector_within_the_range= intersect(find(input_vector>=range_lower_limit),find(input_vector<=range_upper_limit))

input_vector(
indices_in_input_vector_within_the_range)

Answer 4

[Wupadrasta Santosh Kumar]

My simple take would be:

range = [1 10];
xRange = [5 2 1 -1 5 67 3];
decisionV = (ones(length(xRange),1)*range - (ones(2,1)*xRange)')>0;
OutDecision = ~xor(decisionV(:,1),decisionV(:,2));
xRange(OutDecision) = [];