Write a function that will take in a simplex tableau and an associated basis, and return the initial feasible

Please help me with this question.. I have attached the.m file of my code.

Also, here is the sample tableau and basis

tableau = [0 -2 0 0 0;
           1 -1 1 0 4;
          -1  1 0 1 1]
basis = [3; 4]

[the cyclist]

I don't see an attached file. You might want to edit your question and try to attach it again.

[Guillaume]

The attachement is missing and the question is not clear.

I assume you're a french speaker, in which case tableau probably mean array, but I've no idea what you mean by the initial feasible.

[LG]

so its not exactly uploading but.. here's the code.

function [x, z] = readSolution(tableau, basis)
tableau = tableau(:,[2:end]);
basis = tableau(:,end);
x = linsolve(tableau, basis)
z = tableau(1,:)
end

[John D'Errico]

Actually, tableau is the phrase usually used for linear programming. At least it was for me, and my command of French is limited to what I learned (poorly at that) in the 6th grade.

[LG]

or how about this, im not understanding the error that matlab is giving me..

Attempted to access basis(3); index out of bounds because numel(basis)=2.

Error in readSolution (line 6) x(basis(i+1),1)=sol(i,1);

[LG]

that's a different code

[Søren Jensen]

numel means number of elements, so you are trying to access basis(3) which is impossible because basis only has 2 elements..

the error occurs at line 6, when you itterate the basis index

[LG]

okay so how would I not try to access basis(3)

[Søren Jensen]

i do not know the whole code, so i can't know what you want to do exactly, but:

"basis(i+1)" cannot be higher than "basis(2)" because you only have 2 elements in the basis vector.. Therefore the only possible values of "i" is 0 and 1.

if you want to iterate i further than 1 in the code you gave your basis vector must be longer.

If you don't want your basis vector to be longer than 2 you have to think about the logic in your iterations.