Need help to removing motion (breathing?) artifact from ECG signal

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I have this single-channel ECG signal with motion artifacts (I believe from breathing).
I've tried several filters, but none have given me a good output.
Not being an expert, I followed the instructions from Kher, 2019 with this code, but a compatibility issue (since I am using version 2018b) prevents me from obtaining any results; by changing some commands the result is unsuitable:
y1 = load('EKG.mat');
y2= (y1 (:,1)); % ECG signal data
a1= (y1 (:,1)); % accelerometer x-axis data
a2= (y1 (:,1)); % accelerometer y-axis data
a3= (y1 (:,1)); % accelerometer z-axis data
y2 = y2/max(y2);
Subplot (3, 1, 1), plot (y2), title ('ECG Signal with motion artifacts'), grid on
a = a1+a2+a3;
a = a/max(a);
mu= 0.0008;
%Hd = adaptfilt.lms(32, mu); %original command
Hd = dsp.LMSFilter('Length', 32, 'StepSize', mu);
% [s2, e] = filter(Hd, a, y2); % original command, don't work in 2018b version
[s2, e] = Hd(a, y2); % command adapted
fig = figure
subplot (3, 1, 2)
plot (s2)
title ('Noise (motion artifact) estimate')
grid on
subplot (3, 1, 3)
plot (e)
title ('Adaptively filtered/ Noise free ECG signal')
grid on
I also tried filtering in this other way, but the result is very poor.
ecg_signal = load('EKG.mat');
Fs = 256;
t = (0:length(ecg_signal)-1) / Fs;
fc = 45; % cut frequency
[b, a] = butter(4, fc / (Fs / 2), 'low');
% filter
ecg_filtered = filtfilt(b, a, ecg_signal);
With simple low-pass or high-pass filters I wasn't able to obtain at least acceptable results.
If anyone can help me?
thank you in advance
  4 Comments
Mathieu NOE
Mathieu NOE on 29 Aug 2024
can you show us a section with artifacts vs a clean section ? tx
Simone Arno
Simone Arno on 29 Aug 2024
Edited: Simone Arno on 29 Aug 2024
the entire trace of this subject shows these artifacts. this one in the photo is without these artifacts

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Accepted Answer

Star Strider
Star Strider on 29 Aug 2024
There does not appear to be much noise at all, however the small baseline variation and high-frequency noise can be eliminated with an appropriiately-designed bandpass filter.
Try this —
LD = load('EKG.mat')
LD = struct with fields:
data256hz: [118752x1 table]
EKG = LD.data256hz{:,1};
Fs = 256; % No Time Vector Supplied, So Create One
t = linspace(0, numel(EKG)-1, numel(EKG)).'/Fs;
figure
plot(t, EKG)
grid
xlim('tight')
xlabel('Time (s)')
ylabel('Amplitude (V)')
title('Unprocessed EKG Signal')
figure
plot(t, EKG)
grid
xlim([0 5])
xlabel('Time (s)')
ylabel('Amplitude (V)')
title('Unprocessed EKG Signal (Detail)')
[FTs1,Fv] = FFT1(EKG,t);
figure
plot(Fv, abs(FTs1)*2)
grid
xlim('tight')
xlabel('Frequency (Hz)')
ylabel('Magnitude (V)')
title('Fourier Transform')
figure
plot(Fv, abs(FTs1)*2)
grid
xlim([0 10])
xlabel('Frequency (Hz)')
ylabel('Magnitude (V)')
title('Fourier Transform (Detail)')
EKG = [ones(100,1)*EKG(1); EKG]; % Pre-Appeend 'ones' Veector To Eliiminate Starting Transient
EKG_filt = bandpass(EKG, [1, 45], Fs, 'ImpulseResponse','iir'); % Filter With Elliptic IIR Bandpass Filter
EKG_filt = EKG_filt(101:end);
figure
plot(t, EKG_filt)
grid
xlim([0 5])
xlabel('Time (s)')
ylabel('Amplitude (V)')
title('Bandpass-Filtered EKG Signal (Detail)')
function [FTs1,Fv] = FFT1(s,t)
% Arguments:
% s: Signal Vector Or Matrix
% t: Associated Time Vector
t = t(:);
L = numel(t);
if size(s,2) == L
s = s.';
end
Fs = 1/mean(diff(t));
Fn = Fs/2;
NFFT = 2^nextpow2(L);
FTs = fft((s - mean(s)) .* hann(L).*ones(1,size(s,2)), NFFT)/sum(hann(L));
Fv = Fs*(0:(NFFT/2))/NFFT;
% Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
FTs1 = FTs(Iv,:);
end
Use the Fourier transform results to guide the filter design.
.
  2 Comments
Simone Arno
Simone Arno on 30 Aug 2024
Edited: Simone Arno on 30 Aug 2024
thanks a lot, this seems accurate without cutting out too much of the signal. Even though it wasn't very noisy, those few artifacts still made it hard to calculate the QRS complex
where can I find the FFT1.m command? It's not in the installed Signal Processing Toolbox
Star Strider
Star Strider on 30 Aug 2024
As always, my pleasure!
The ‘FFT1’ function is one I wrote, and appended at the end of the code I posted:
function [FTs1,Fv] = FFT1(s,t)
% Arguments:
% s: Signal Vector Or Matrix
% t: Associated Time Vector
t = t(:);
L = numel(t);
if size(s,2) == L
s = s.';
end
Fs = 1/mean(diff(t));
Fn = Fs/2;
NFFT = 2^nextpow2(L);
FTs = fft((s - mean(s)) .* hann(L).*ones(1,size(s,2)), NFFT)/sum(hann(L));
Fv = Fs*(0:(NFFT/2))/NFFT;
% Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
FTs1 = FTs(Iv,:);
end
Feel free to copy it and use it. If you save it as a separate file on your MATLAB search path, name that file FFT1.m.
.

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More Answers (1)

Image Analyst
Image Analyst on 29 Aug 2024
I'm sure it's been done before. Rather than me just guessing, I suggest you search the medical literature in PubMed to find articles that show how it's done.

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