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Replace the element in the cell array with space inbetween

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I have a cell array element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
I need to replace num riqu = numeric
con tant = constant
how can I do this ?

Accepted Answer

Guillaume
Guillaume on 6 May 2015
It's not clear how generic of an answer you are looking for. In you particular example, the simplest way would be:
c = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'};
c(strcmp(c, 'num riqu')) = {'numeric'};
c(strcmp(c, 'con tant')) = {'constant'}
  3 Comments
Guillaume
Guillaume on 6 May 2015
You would have to use one regexprep per expression you want to replace, so while you could do it, it wouldn't be any simpler.
In any case, as defined in your example, the search patterns don't need regular expressions.

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More Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 6 May 2015
element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=strrep(element,'num riqu','numeric');
element=strrep(element,'con tant','constant')
  2 Comments
Azzi Abdelmalek
Azzi Abdelmalek on 6 May 2015
element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=regexprep(element,'num riqu','numeric')
element=regexprep(element,'con tant','constant')
But strrep is faster then regexprep

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