rotation of 3D XYZ points by an ijk unit vector
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Andrew Dickins
on 6 Nov 2024 at 13:07
Edited: Bruno Luong
on 7 Nov 2024 at 10:00
I have a XYZ co-ordinate points that I would like to rotate around the origin from one vector of a defined plane to another. For example I have a unit surface vector of a plane of [0.9997 -0.0240 -0.0053] and I would like to rotation my points so that this planes normal is parallel to the X axis [1 0 0].
How can I take my [X Y Z] co-ordinates and rotate them in 3 dimensions from vector [0.9997 -0.0240 -0.0053] to [1 0 0]
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Bruno Luong
on 6 Nov 2024 at 13:52
Edited: Bruno Luong
on 6 Nov 2024 at 14:54
% source and target unit vectors
u = [0.9997; -0.0240; -0.0053] ; u = u/norm(u);
v = [1; 0; 0]; v = v/norm(v);
% Compute 3 x 3 rotation matrix R so that R*u is v
% see here foe ref of angle calculation
% https://www.mathworks.com/matlabcentral/answers/101590-how-can-i-determine-the-angle-between-two-vectors-in-matlab?s_tid=srchtitle
M = makehgtform("axisrotate",cross(u,v),2*atan(norm(u-v)/norm(u+v)));
R = M(1:3,1:3);
XYZ = [u, randn(3,6)], % (3 x n) your n data point coordinates
XYZ_Rotates = R*XYZ % observe the first vector u after rotation becomes v
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Bruno Luong
on 7 Nov 2024 at 9:42
Edited: Bruno Luong
on 7 Nov 2024 at 10:00
Note that the choice here of axis rotation vector r := cross(u,v) is not unique; but it's the one that implies a smallest rotation angle.
Any unit vector that has the same distance to u and v can be setected as axis of rotation.
For example normalized (u+v)/2. The angle here is pi, the largest possible choice.
% source and target unit vectors
u = [0.9997; -0.0240; -0.0053] ; u = u/norm(u);
v = [1; 0; 0]; v = v/norm(v);
% Compute 3 x 3 rotation matrix R so that R*u is v
M = makehgtform("axisrotate",(u+v)/2,pi);
R = M(1:3,1:3);
XYZ = [u, randn(3,6)], % (3 x n) your n data point coordinates
XYZ_Rotates = R*XYZ % observe the first vector u after rotation becomes v
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