How to complete this if-else statement for minesweeper.
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% Step2: add the numbers to each bomb location based on number of bombs its
% touching
BoardFINAL = board;
for r = 1:1:row
for c = 1:1:col
if Board(r,c) ~= -1
if r == 1 && c == 1
AROUND = [Board(r,c+1),Board(r+1,c),Board(r+1,c+1)];
BOMBcount = abs(sum(AROUND));
BoardFINAL(r,c) = BOMBcount;
elseif r == 1 && c == col
elseif
elseif
elseif r == 1
elseif
elseif
elseif
else
AROUND = [Board(r-1,c-1),Board(r-1,c),Board(r-1,c+1),Board(r,c-1),Board(r,c+1),Board(r+1,c-1),Board(r+1,c),Board(r+1,c+1)]
BOMBcount = abs(sum(AROUND));
BoardFINAL = (r,c) = BOMBcount;
end
end
end
end
I was able to figure out the first part but stuck on the rest.
1 Comment
Walter Roberson
on 8 Nov 2024
Suppose Board(1,2) = 1 and Board(2,1) = -1 and Board(2,2) = 0, and suppose Board(1,1) is not -1. Then sum([1,-1,0]) would be 0. The bomb count for Board(1,1) would be determined to be 0, even though there are bombs adjacent to it.
It seems clear that you should not be taking abs(sum(AROUND))
Answers (1)
Walter Roberson
on 8 Nov 2024
0 votes
You can do the calculations without if/elseif .
Use max(1,r-1:r+1) to clip against the top margin. Use min(row, r-1:r+1) to clip against the bottom margin.
Do likewise for columns.
The resulting range of subscripts will be suitable for indexing just the appropriate box at each point.
3 Comments
Walter Roberson
on 8 Nov 2024
Alternately, take your array and pad it on left, right, top bottom with 0. Now you can always just access padded_board(r:r+2,c:c+2) without exceeding the array bounds; you will get the 0 of the padding margin anyplace that you would otherwise have gone outside the bounds.
Joshua
on 9 Nov 2024
Walter Roberson
on 9 Nov 2024
elseif r == 1 && c == col
AROUND = [Board(r,c-1),Board(r+1,c),Board(r+1,c-1)];
and so on.
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