How can I load my data from a variable filename

Hello, How can I load 80 files(.mat) from folder each has a number ex: file_1, file_2, file_3 ...file_80. What I did the following:

for x= 1:80
load ('file_x.mat')

But it's not working: gave me the following error: Error using load Unable to read file 'file_x.mat': no such file or directory.

Answer 1

[Sebastian Castro]

You need to do this by converting the numerical value of "x" to a string and concatenating that with the rest of the file name string. For example:

for x= 1:80
  load (['file_' num2str(x) '.mat'])
end

- Sebastian

[Stephen23]

Note that it is much better to assign the data into an output variable, like this:

for k = 80:-1:1
   S(k) = load(sprintf('file_%d.mat',k));
end

This avoids the need to dynamically name and access those variables.

[Sebastian Castro]

Good call. Thanks for the answer upgrade!

[Marta Caneda Portela]

I have a question because I have the same problem but the files are named file_000000 until file_000788. How would I do that? Thank you!

[Steven Lord]

Are those the only files with that pattern of name in your directory?

D = dir('file_000*');
for k = 1:numel(D)
    fprintf('Processing file %s.\n', D(k).name)
end

[Shahzanani Senin]

I have the question also because I have the same problem to load the data. I have 248 files with different name which is 94 files of ADmaskMean_AD_1 until ADmaskMean_AD_94, and 154 files of ADmaskMean_NORMAL_1 until ADmaskMean_NORMAL_154. How can I do that? Thank you!