Image processing using indexing

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Dana
Dana on 15 Dec 2011
Hi. I am wondering if anyone can help me. I'm not sure wether this is possible but i will try to explain it as best I can.
I have two images with the same resolution.
Image A, a RGB image.
Image B, a Gray scale image the with only a small region of postive values the rest black (0 values).
I wish to map a jet colormap to Image B and substitute these potive pixels into image A (repleaceing the pixels from A)
I understand that a grayscale image with a colormap is of a different format to a RGB image which is (m*n*3). But is it possible.
I hope i have explained it clearly enough.
I would be gratefull for any help. Thank you
Regards Dana

Accepted Answer

David Young
David Young on 15 Dec 2011
The details depend on what class your images are, but here's an example that you can probably modify as needed.
% test data - an rgb image and a greyscale image the same size, with lots
% of zeros in it
A = imread('saturn.png');
p = imread('pout.tif');
B = zeros(size(A,1), size(A,2), class(p));
B(1001:1000+size(p,1), 501:500+size(p,2)) = p;
% apply the jet map to the greyscale image
if strcmp(class(B), 'double')
% assume values in range 0-1
Brgb = ind2rgb(B, jet);
else
nvals = double(intmax(class(B))) + 1;
Brgb = ind2rgb(B, nvals*jet(nvals));
end
% copy non-zero parts of B into A
ind = repmat(B ~= 0, [1 1 3]); % index array
Amod = A;
Amod(ind) = Brgb(ind);
% look at the result
imshow(Amod);
  5 Comments
David Young
David Young on 15 Dec 2011
... and I'd recommend looking at the demo that Image Analyst mentions below, though you might want to get my simpler code going first.
Dana
Dana on 16 Dec 2011
Hey David, Thanks for your help I have spent all this morning playing around with your code but i have gotten it working.
My problem was that image p = imread('pout.tif'); is a smaller size than image A = imread('saturn.png');
I did not realise that the lines:
B = zeros(size(A,1), size(A,2), class(p));
B(1001:1000+size(p,1), 501:500+size(p,2)) = p;
were creating an image the same size as A and placing the photo in it.
So i cut down the code to
nvals = double(intmax(class(B))) + 1;
Brgb = ind2rgb(B, nvals*jet(nvals));
ind = repmat(B ~= 0, [1 1 3]); % index array
Amod = A;
Amod(ind) = Brgb(ind);
% look at the result
imshow(Amod);
As my images are already the same size and unit 8.
I also applied my own colormap which took some playing around but it worked.
So thanks again for your help, you really helped me out I cant believe the solution was so simple. You should have seen the code i had written myself to try and solve this.
Regards
Dana

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More Answers (1)

Image Analyst
Image Analyst on 15 Dec 2011
Dana: See my full blown demo in another related posting:
  1 Comment
Dana
Dana on 16 Dec 2011
Thanks for your help. You demo was very informative

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