What am I doing wrong in my code? Trying to detect if array has NaN.

So this is my code:

 x = [ NaN NaN 24 ]

    if isnan(x)==1
        A=2
    else 
        A=min(x)
    end

So I have this code. What I want it to do is to see if there are any NaN's in the vector. If there is an NaN then we make A be 2. If there isn't then A is just the the minimum number of x which is essentially 24.

But when I execute the program it keeps saying A=24 when it should be NaN. Any help would be greaty appreciated.

Answer 1

[Rick Rosson]

   if any(isnan(x))