how to change each cell color in a uitable
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Mahmoud Hassan Eldally
on 31 Dec 2011
Commented: Craig
on 24 Jul 2024
I wonder how can i make a uitable such that cells at this table has different background colorsand each column has different width
thank you
1 Comment
Emmanuelle Fried
on 28 Jun 2021
Use addStyle:
uit = uitable(...);
s = uistyle('BackgroundColor','red');
addStyle(uit,s,'column',2)
Accepted Answer
Friedrich
on 3 Jan 2012
Edited: Eric Sargent
on 11 Feb 2023
Update:
f = uifigure;
uit = uitable(f, Data = "hi");
s = uistyle('BackgroundColor','red');
addStyle(uit,s,'column',1)
Original Answer
Hi,
this is pretty tricky within an uitable since the text you display will have a red background and not the full cell in the table:
uitable('Data',{'<body bgcolor="#FF0000">Hello</body>'})
You will see that Hello has a read background but thats all.
So we can do a small trick. Instead of adding the text we add a html table which contains the text. In addition this html table is sooooo wide that it needs the full cell^^:
uitable('Data',{'<table border=0 width=400 bgcolor=#FF0000><TR><TD>Hello</TD></TR> </table>' })
So overall you can do a colored table like this:
colergen = @(color,text) ['<table border=0 width=400 bgcolor=',color,'><TR><TD>',text,'</TD></TR> </table>'];
data = { 2.7183 , colergen('#FF0000','Red')
'dummy text' , colergen('#00FF00','Green')
3.1416 , colergen('#0000FF','Blue')
}
uitable('data',data)
14 Comments
Craig
on 24 Jul 2024
Eric Sargent, it would appear that uistyle, addStyle, and removeStyle functions only work on uitable when the uitable is made in a uifigure, but not when a uitable is made in figure. That has me stuck at the moment.
Error using matlab.ui.control.Table/addStyle (line 63)
Functionality not supported with figures created with the figure function.
More Answers (5)
Philip
on 31 Mar 2017
In Matlab 2017a (and at least as far back as 2013b) this has improved. The uitable now has a "BackgroundColor" property. This is an array of n rows and 3 columns, RGB values between 0 and 1. It appears that if this array has less rows than the data in the table, then the colours are repeated throughout the table.
To highlight a single row, create a colour array the same size as your data and specify the row of interest as the colour you want.
This is how the alternating row colours are created (and so those colours can be changed if you want as well).
1 Comment
Torsion27
on 24 Apr 2018
Hello, that is my way to try to get the GUI uitable BAckgroundColor changed. But it is only changing the whole uitable. I want it to just change the row of the checkbox green if the checkbox is 1 and if checkbox is 0, change to red background of the row. Thanks for your help. best regards
function pushbutton2_Callback(hObject, eventdata, handles)
global pushbutton
[num,txt,raw]= xlsread(uigetfile ({'.xlsx'}))
anzahl_kriterien = size([raw],1)% --> aendern
kriterium = cell(anzahl_kriterien);
tabledata = [num2cell(true(length(raw),1)),raw];
set(handles.uitable3, 'data',tabledata) setappdata(handles.uitable3,'RawTableDat',raw)
% --- Executes when entered data in editable cell(s) in uitable3. function uitable3_CellEditCallback(hObject, eventdata, handles) tabledata=get(handles.uitable3,'Data');
spalte1=tabledata(:,1) spalte2=tabledata(:,2)
zeilenanzahl=length(tabledata);
% uitablehandles=findobj(handles.uitable3); for j = 1:1:zeilenanzahl %für zeile 1 bis ende
if (spalte1{j,1}==1)
tabledata{j,2}=spalte2{j,1}
set(handles.uitable3,'BackgroundColor',[0 1 0])
end
for j = 1:1:zeilenanzahl
if (tabledata{j,1}==0)
tabledata{j,2}= set(handles.uitable3,'BackgroundColor',[1 0 0])
end end end
guidata(hObject,handles);
% --- Executes during object creation, after setting all properties. function uitable3_CreateFcn(hObject, eventdata, handles) hObject.ColumnFormat = {'logical',[]}; hObject.ColumnEditable = logical([1 0]);
Walter Roberson
on 31 Dec 2011
4 Comments
Rohail Razzaq
on 15 Apr 2015
what if i have to use a particular variable instead of a specific text in the following line :
html<font color="blue">'my text'</font></html>
Torsion27
on 22 Apr 2018
Edited: Walter Roberson
on 23 Apr 2018
Hey, i have a similar problem with a Gui uitable and it would be great if you can help me with that. Thaks a lot :)
0 Comments
Torsion27
on 24 Apr 2018
Hello, that is my way to try to get the GUI uitable BAckgroundColor changed. But it is only changing the whole uitable. I want it to just change the row of the checkbox green if the checkbox is 1 and if checkbox is 0, change to red background of the row. Thanks for your help. best regards
function pushbutton2_Callback(hObject, eventdata, handles)
global pushbutton
[num,txt,raw]= xlsread(uigetfile ({'.xlsx'}))
anzahl_kriterien = size([raw],1)% --> aendern
kriterium = cell(anzahl_kriterien);
tabledata = [num2cell(true(length(raw),1)),raw];%das nur einmal checkbox spalte da ist und am anfang
set(handles.uitable3, 'data',tabledata)
setappdata(handles.uitable3,'RawTableDat',raw)
% --- Executes when entered data in editable cell(s) in uitable3.
function uitable3_CellEditCallback(hObject, eventdata, handles)
tabledata=get(handles.uitable3,'Data');
spalte1=tabledata(:,1)
spalte2=tabledata(:,2)
zeilenanzahl=length(tabledata);
for j = 1:1:zeilenanzahl %für zeile 1 bis ende
if (spalte1{j,1}==1)
tabledata{j,2}=spalte2{j,1}
set(handles.uitable3,'BackgroundColor',[0 1 0])
end
for j = 1:1:zeilenanzahl
if (tabledata{j,1}==0)
tabledata{j,2}= set(handles.uitable3,'BackgroundColor',[1 0 0])
end
end
end
guidata(hObject,handles);
% --- Executes during object creation, after setting all properties.
function uitable3_CreateFcn(hObject, eventdata, handles)
hObject.ColumnFormat = {'logical',[]};
hObject.ColumnEditable = logical([1 0]);
1 Comment
Himanshu Verma
on 19 May 2020
Hi there...
Did you find any solution to this problem? I'm also looking for the same.
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