Str to Cell (trivial ?)

Hallo there,
I would like to make out of a big string a cell array, e.g.
str1 = ['aa1','bb1','cc1'];
str2 = ['aa2','bb2','cc2'];
Edit : what I mean is a string representing various rows and columns, i.e. strMatrix = [str1 ; str2 ; strN]], which has to be converted into a cell matrix.
The question is how to make out of each comma separated string entry, seperate cell array entry. Im looking for something similar like
dataCell = {eval(str1),';', ...
eval(str2)};
At the end I want to have the following :
dataCell = {'aa1','bb2','cc2'; 'aa2','bb2','cc2'}
Thanks in advance.

6 Comments

C.J. Harris
C.J. Harris on 11 Jan 2012
Your main problem is that once you create the strings 'str1' and 'str2' there is no way of knowing that they were originally three seperate strings, hence splitting them again becomes troublesome.
RubenMath
RubenMath on 11 Jan 2012
So, the only solution is
dataCell {end+1} = 'aa1';
?1?
Daniel Shub
Daniel Shub on 11 Jan 2012
What are you trying to do? Are aa1, bb1, always three characters? What is the original input that you have?
RubenMath
RubenMath on 11 Jan 2012
Im trying to find a performative solution for creating a cell array out of a string array.
Jan
Jan on 11 Jan 2012
@RubenMath: Please consider this:
['aa1', 'bb1', 'cc1'] is identical to 'aa1bb1cc1'
So your inputs are not clear yet.
RubenMath
RubenMath on 12 Jan 2012
what I mean is a string representing various rows and columns, i.e. strMatrix = [str1 ; str2 ; strN], which has to be converted into a cell matrix.

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Answers (1)

Daniel Shub
Daniel Shub on 11 Jan 2012
What about
str1 = {'aa1','bb1','cc1'};
str2 = {'aa2','bb2','cc2'};
dataCell = [str1; str2];

3 Comments

If the str1 and str2 are already given as cell arrays you might just write
dataCell=[str1; str2];
But I guess the main question is still: how do the original strings look like? str1 in the original question is just 'aa1bb1cc1'.
Titus
Jan
Jan on 11 Jan 2012
@Daniel: {str1{:};str2{:}} is less efficient than [str1; str2].
Daniel Shub
Daniel Shub on 12 Jan 2012
Of course it is. Thanks guys. I edited the answer.

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