Answered

Division with negative powers

u = [0 0 1 0 1]; v = [1 4 4 4 3]; Result = filter(u,v,[1, zeros(1,7)]) ans = 0 0 1 -4 13 -40 121 -364

Division with negative powers

u = [0 0 1 0 1]; v = [1 4 4 4 3]; Result = filter(u,v,[1, zeros(1,7)]) ans = 0 0 1 -4 13 -40 121 -364

2 years ago | 1

| accepted

Answered

How to add 'Description' to '.jpeg'?

If you're only interested in the 'Comment' field, then you can set it directly: imwrite(i,'figC.jpg', 'Comment', 'Made with...

How to add 'Description' to '.jpeg'?

If you're only interested in the 'Comment' field, then you can set it directly: imwrite(i,'figC.jpg', 'Comment', 'Made with...

2 years ago | 0

| accepted

Answered

How to make array with first values of matrix

% Input A = [1 2 3 4 5 6 7 8 9 10;2 2 3 3 4 5 5 2 3 3]'; % Result B = A([boolean(1); diff(A(:,2))~=0],1);

How to make array with first values of matrix

% Input A = [1 2 3 4 5 6 7 8 9 10;2 2 3 3 4 5 5 2 3 3]'; % Result B = A([boolean(1); diff(A(:,2))~=0],1);

2 years ago | 0

Answered

How do I read strings with textscan?

Have you tried specifying the delimiter? formatSpec = '%d %s %f %f %f %f %f %f %f %f %f'; C = textscan(fid,formatSpec,15...

How do I read strings with textscan?

Have you tried specifying the delimiter? formatSpec = '%d %s %f %f %f %f %f %f %f %f %f'; C = textscan(fid,formatSpec,15...

2 years ago | 0

Answered

Help with dec2hex (case sensitive and Zero)

You could change the line: CarsHex=dec2hex(CarsDecimal); to: CarsHex=lower(arrayfun(@(x) (dec2hex(x)), CarsDecimal,...

Help with dec2hex (case sensitive and Zero)

You could change the line: CarsHex=dec2hex(CarsDecimal); to: CarsHex=lower(arrayfun(@(x) (dec2hex(x)), CarsDecimal,...

2 years ago | 1

| accepted

Answered

not enough input argument

Your code, which I've included below takes two inputs, x and y, however you don't use the first input 'x' anywhere in your code,...

not enough input argument

Your code, which I've included below takes two inputs, x and y, however you don't use the first input 'x' anywhere in your code,...

2 years ago | 0

Answered

Why this code is error???

Because given your definitions of x and y, the expression _3+(-x)+(-y)_ results in [3 1 -1 -3], and you cannot calculate the fac...

Why this code is error???

Because given your definitions of x and y, the expression _3+(-x)+(-y)_ results in [3 1 -1 -3], and you cannot calculate the fac...

2 years ago | 0

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