how to define a while statement that when the variable equals a numerical value, ends the code?
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bilgesu ak
on 19 Jan 2016
Commented: bilgesu ak
on 19 Jan 2016
Hi,
I want to write a while condition that when variable A gets a numerical value inside the loop, ends the code, otherwise continues to the code...
How can I write this while condition?
Thansks in advance,
Regards...
0 Comments
Accepted Answer
Walter Roberson
on 19 Jan 2016
while ~exist('A', 'var') && ~isnumeric(A)
...
end
This will continue to loop until A is assigned a value and the value is numeric.
The common kinds of values that are not numeric include logical values, character strings, structures, cell arrays, function handles, graphics objects (R2014b or later), and various other kinds of objects.
3 Comments
Walter Roberson
on 19 Jan 2016
while ~exist('A', 'var') || ~isnumeric(A) || isempty(A)
...
end
You would not need to initialize A at all
[] is type double and so is considered a numeric value. However I have added that as a condition.
More Answers (1)
Titus Edelhofer
on 19 Jan 2016
Hi,
I understand the "get's value" is meant as "being not empty" ...?
A = [];
while isempty(A)
% do something, e.g.
A = 42;
end
Titus
2 Comments
Titus Edelhofer
on 19 Jan 2016
Or, if you want to run while it's not a specified value:
A = 10;
while A~=1
% do something, e.g.
A = A - 1;
end
Titus
Walter Roberson
on 19 Jan 2016
And be careful, if your "specified value" is not an integer then it might be difficult to match it exactly due to floating point precision issues.
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