Using unique command in a matrix

Dear all, I would like to delete the columns of a matrix according to the unique values of its row. More specifically: Suppose to have this matrix: A =
1 2 3 3 3 5 6
11 14 16 16 16 14 16
I would like to select the unique values of the first row: [1 2 3 5 6] and create the matrix: A =
1 2 3 5 6
11 14 16 14 16
Anyone who can help me?

1 Comment

Your result is unambiguous only because in your example, the replicates of '3' in the first row coincide with replicates of '16' in the second row. What if the original matrix looks like this:
1 2 3 3 3 5 6
11 14 16 17 18 14 16
What goes under the '3' in the result? Will it be 16, 17, or 18?

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Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 10 Feb 2016
Edited: Azzi Abdelmalek on 10 Feb 2016
A=[1 2 3 3 3 5 6
11 14 16 16 16 14 16]
B=unique(A','rows')'
Or maybe you want this
[ ~,jj]=unique(A(1,:))
B=A(:,jj)

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Asked:

on 10 Feb 2016

Edited:

on 10 Feb 2016

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