Computing and Ploting Fourier transform

3 views (last 30 days)
How can i use the fft command to transform a rectangular pulse to sinc function and plot the sinc function, i'm using a very traditional way to compute the fourier transform and plot it, but this way is too slow, when i use the fft command and try to plot, the ploting of the magnitude is only the pins or a spike, i need the plot to be a sinc function as the picture that i attached here, also i'm using the same method to compute the inverse fourier transform so i also need to use the ifft command, can anyone help?
if true
p = heaviside(t+1)-heaviside(t-1);
k = 0;
F=zeros(1,8001);
for f= -4:0.001:4
k=k+1;
F(k) = trapz(t,p.*exp(-1i*2*pi*f*t));
end
f = -4:0.001:4;
figure(1);
plot(f,F);
grid
end

Accepted Answer

Rick Rosson
Rick Rosson on 21 Feb 2016
Edited: Rick Rosson on 21 Feb 2016
Fs = 8;
dt = 1/Fs;
N = 8000;
t = dt*(-N/2:N/2-1)';
dF = Fs/N;
f = -Fs/2:dF:Fs/2-dF;
p = heaviside(t+1)-heaviside(t-1);
P = dt*fftshift(fft(ifftshift(p)));
figure;
plot(f,real(P));
grid on;
  1 Comment
omarahmed.m
omarahmed.m on 21 Feb 2016
Thank you for your response, Could you just specify this command "P = dt*fftshift(fft(ifftshift(p)));", why it consist of fftshift of fft of ifftshift, and why multiplying by "dt". thank you very much.

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!