Transposing 3 D matrix using permute - how does permute work?

Ok. So I see how to transpose all the "2D slices" of a 3D matrix on other answers (permute(A, [2 1 3])).
But what does the order vector mean? The 2 means what? The second row, column? Anyone who can explain this, I appreciate it.
Thanks

2 Comments

Have you tried "doc permute" yet?
Hi, Order vector [1:first dim(row) 2:second dim(col) 3:third dim(Z)] so if you want to transpose rows and columns keeping the same Z, your vector would be [2 1 3]

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 Accepted Answer

It is the dimension number. In [2 1 3] it means that the second dimension of the original should become the first dimension of the new array, and the first dimension of the original should become the second dimension of the new array, and the third dimension of the original should stay where it is.

More Answers (2)

Another way to do 2D slice transposing of an nD Array:
mtimesx(1,A,'t')
You can find mtimesx on the FEX here:
href=""<http://www.mathworks.com/matlabcentral/fileexchange/25977-mtimesx-fast-matrix-multiply-with-multi-dimensional-support</a>>
Hello all,
Yeah.. I checked the docs before posted the message. I got it now. Thanks.
I think the docs could be improved a little bit, like an example.
A = [1 2; 3 4]
NewA = permute(A, [2,1,3])
=>
A(1,1) => NewA(1,1)
A(1,2) => NewA(2,1)
A(2,1) => NewA(1,2)
A(2,2) => NewA(2,2)
NewA = [1 3; 2 4]

2 Comments

The third dimension has length 1, and it is left where it is, so the third dimension is 1 afterwards. Trailing 1's from the third dimension onward are not explicitly shown in MATLAB. An array which is 2x2 is also 2x2x1x1x1x1x1 but it would not serve any useful purpose to explicitly display the 250-some-odd trailing subscripts that are all exactly "1".
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Asked:

Ali
on 24 Jan 2012

Commented:

on 7 Mar 2018

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