How to implement a for loop over a specified range?

Outputs:
  • t: time vector ranging from Start to End with a sampling rate of fs
  • X: sum of sinusoids over the specified range
The code I am using for my outputs is:
t = linspace(Start,End,fs);
X=0;
for i=1:N
X = X + A(i)*cos(2*pi*f(i)*t + phi(i)) + B(i);
end
I keep getting an error: Attempted to access B(2); index out of bounds because numel(B)=1. Need help fixing it.

2 Comments

We do not know how you initialized B, or what it is intended to mean.
Did you happen to compute B using the "/" operator?
I got the same error for A too. Both B and A are N*1 matrix, where N is a integer, and positive. This is how I coded and initialized both A and B.
A = [N,1];
if ~all(isreal(A)) || ~all(A>0)
error('Amplitude must be real and postive elements');
end
B = [N,1];
if ~all(isreal(B))
error('B must be real and postive elements');
end

Sign in to comment.

 Accepted Answer

The code you posted would result in A and B being scalars (length 1) if N is empty. If N was not empty, then A and B would only be of length 2 anyhow.
If you are trying to initialize A to be a vector of length N then you would use something like
A = zeros(N, 1);
... but then it would be all zero, which doesn't sound very meaningful.

3 Comments

Maybe instead of using zeros, how could I could use random values that create a N * 1 matrix. How could I code that, so lets say N is equal to 10, and then A is equal to a 10 * 1 matrix. How could I make A be assigned to random values that generate a vector length of 10 rows and 1 column?
thanks for your help, I understand it a lot better now

Sign in to comment.

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!