Function definitions are not permitted in this context. is the error

function y=minutie(x)
i=ceil(size(x)/2);
if x(i,i)==0;
Y=0;
else
Y=sum(x(:))-1;
end

[Image Analyst]

Please complete your question.

Answer 1

[Walter Roberson]

size(x) is a vector, even when x is a scalar or a vector. So i=ceil(size(x)/2) will have i be a vector. Then you use x(i,i) which is indexing x with that vector at each of the two indices, which would be a request to test 4 different locations (a 2 x 2 subarray). This would also fail if x is more than twice as long as it is wide or more than twice as wide as it is long.

Instead, check x(i(1), x(i(2))

Or, more simply, check

   x( ceil(numel(x)/2) )

as that spot is going to be right in the middle of the array