Count the length of repeated value sets in an array?

Sorry if my question title is confusing -

For a given binary array, I'm trying to count the total length of consecutive sets of ones.

For example, x = [1 0 0 1 1 1 0 1 0 1 1 0 0 0]

should result in [1 3 1 2]

Any help is appreciated :)

Answer 1

[Azzi Abdelmalek]

x = [1 0 0 1 1 1 0 1 0 1 1 0 0 0]
out=nonzeros(accumarray(nonzeros(x.*(cumsum(~x)+1)),1))

Answer 2

[Roger Stafford]

   f = find(diff([false,x==1,false])~=0);
   L = f(2:2:end)-f(1:2:end-1);

[Nicolas]

Worked perfectly, thank you!

Answer 3

[Andrei Bobrov]

x = [1 0 0 1 1 1 0 1 0 1 1 0 0 0];

t = cumsum(diff([0;x(:)])==1).*x(:);
out =  accumarray(t(t>0),1);

or

t = bwlabel(x(:));
out = accumarray(t(t>0),1);