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how to store n matrix in an other matrix of size n

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Hi, i have a loop FOR i=1:N. For each 'i', i have to create 3 matrices that i want to store in the position 'i' of a new matrix(N,3). How can i do that? Thanks
  2 Comments
parth pandya
parth pandya on 20 May 2016
Edited: parth pandya on 20 May 2016
Your Main matrix will be (N,3) size.
what is size of 3 matrices you are going to create?
& what do you mean by 'i' position?
Can you explain?
loukil sana
loukil sana on 20 May 2016
*First, i will create: * mat1(4,6) * mat2(4,6) * mat3(4,2) * and a value (an integer) * Then, i will execute those 3 matrices+the integer N time. * Finaly, i create the matrix of (N,4) just to memories those results that i have cited(the matrices+the integer)

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Accepted Answer

John D'Errico
John D'Errico on 20 May 2016
Edited: John D'Errico on 20 May 2016
Learn what a cell array is, how to use them, how to define them.
doc cell
You can also do similar things with structs.
  3 Comments
John D'Errico
John D'Errico on 20 May 2016
Edited: John D'Errico on 20 May 2016
So? A cell array can contain anything.
N = 10;
C = cell(N,3);
C{1,1} = pi;
C{1,2} = rand(3,3);
C1,3} = 'The sky is falling!';
etc.
loukil sana
loukil sana on 20 May 2016
ok now i have done that but when i do the implementation it doesn't post up the matrices with values ... but juste the dimmension of the matrices. And an other thing is that it post up juste the last raw of the matrix and not all the raws that he has memoriesed
--------------------------------------------------------------
Matrix containing the initial population of 5 individual
[] [] [] []
[] [] [] []
[4x6 double] [4x6 double] [4x2 double] [19]
[] [] [] []
[] [] [] []

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More Answers (2)

parth pandya
parth pandya on 20 May 2016
you can try this:
N = 1;
MainMatrix = cell(N,4);
Result1 = zeros(4,6);
Result2 = zeros(4,6);
Result3 = zeros(4,2);
i = 2;
MainMatrix{1,1} = Result1;
MainMatrix{1,2} = Result2;
MainMatrix{1,3} = Result3;
MainMatrix{1,4} = i;
Also you can read
doc struct
  2 Comments
loukil sana
loukil sana on 20 May 2016
Thank you sir. But i have something that can't work with that. Can i have your email that i can send you my code if it's possible. thakns My mail is: loukil.sanaa@gmail.com

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Azzi Abdelmalek
Azzi Abdelmalek on 20 May 2016
Edited: Azzi Abdelmalek on 20 May 2016
If your matrices have the same size (nxm), you can use nxmxp matrix. For example
A1=[1 2;3 4;5 6];
A2=[7 8;9 10;1 1];
You can create the matrix B:
[n,m]=size(A1);
p=2;
B=zeros(n,m,p);
B(:,:,1)=A;
B(:,:,2)=B;
B
  2 Comments
loukil sana
loukil sana on 20 May 2016
thanks for your answer, but no matrices don't have the same size. *mat1(4,6) *mat2(4,6) *mat3(4,2) *and i have a value also (integer)
loukil sana
loukil sana on 20 May 2016
i have to mention that the 3 matrices containt values( they are a result). In other word, i create the matrix of (N,3) just to memories the result i get each time because i need them later.

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