How can i make this loop start at theta= zero and evaluate the same equations for values increasing by two (e.i at 0,2,4,6 etc.)
3 views (last 30 days)
Show older comments
Emily Gobreski
on 11 Jun 2016
Commented: Emily Gobreski
on 12 Jun 2016
n=(360/Dth)+1
Trial>> for I=1:2:n R=12
w=(2*pi/5) Md=50 Theta=0 Thetarads= theta*pi/180
Id=(.5*Md*R^2)
Mp=75
Mb=30
alpha=0 u=.8 L=6*R theta=0 Dth=2 thetarads=theta*pi/180 rx=(R)*cos(theta)-L*cos(180)-L ry=(R*sin(theta))-(L*sin(180))-(R*sin(theta)) vx=(-R)*(w)*sin(theta) vy=(R)*(w)*cos(theta) alpha=0 ax=(-R)*alpha*sin(theta)-(R*(w^2)*cos(theta)) ay=(R)*alpha*cos(theta)-(R*w^2*sin(theta)) theta=theta+Dth end
2 Comments
Chad Greene
on 11 Jun 2016
What equations do you need to evaluate for each I? It's generally good to do as little as possible inside a loop. For example, you can evaluate Mp=75 just once before the loop rather than computing it every time.
A small note: It's much easier to read and run your code if you can format it using the {}Code button when posting a question.
Accepted Answer
Chad Greene
on 11 Jun 2016
Here's how you'd get ax and ay. First we define an array of values theta which go from 0 to 360 in steps of 2. Then we say for each value of theta, compute a corresponding value of ax and ay. I'm using k as a counter which goes through each index in theta.
R = 12;
w = 2*pi/5;
alpha = 0;
theta = 0:2:360;
for k = 1:length(theta)
ax(k)=(-R)*alpha*sind(theta(k))-(R*(w^2)*cosd(theta(k))) ;
ay(k)=(R)*alpha*cosd(theta(k))-(R*w^2*sind(theta(k))) ;
end
2 Comments
Chad Greene
on 11 Jun 2016
Here are the plotted results of ax and ay:
plot(ax,ay)
axis equal
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/183582/image.png)
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!