Finding a row with a certain condition

Assume I have the following matrix.

733458  91  1.01510000000000  1.01680000000000  1.01490000000000  1.01520000000000  1.01585000000000
733458  112  1.01620000000000  1.01620000000000  1.01400000000000  1.01610000000000  1.01510000000000
733458  135  1.01440000000000  1.01540000000000  1.01430000000000  1.01480000000000  1.01485000000000
733458  154  1.01420000000000  1.01580000000000  1.01410000000000  1.01420000000000  1.01495000000000
733458  173  1.01550000000000  1.01570000000000  1.01490000000000  1.01560000000000  1.01530000000000

I want to find the row that contains in column one the value 733458 and that is the closest to 158 in column 2. How can I do that?

[Muhammad Usman Saleem]

use logical operator

Answer 1

[Azzi Abdelmalek]

A=[733458  91  1.01510000000000  1.01680000000000  1.01490000000000  1.01520000000000  1.01585000000000
733458  112  1.01620000000000  1.01620000000000  1.01400000000000  1.01610000000000  1.01510000000000
733458  135  1.01440000000000  1.01540000000000  1.01430000000000  1.01480000000000  1.01485000000000
733458  154  1.01420000000000  1.01580000000000  1.01410000000000  1.01420000000000  1.01495000000000
733459  173  1.01550000000000  1.01570000000000  1.01490000000000  1.01560000000000  1.01530000000000]
ii=ismember(A(:,1),733458)
B=A(ii,:)
[~,jj]=min(abs(A(ii,2)-158))
out=B(jj,:)

Answer 2

[Star Strider]

One approach:

x = 158;
idx = find((M(:,1) == 733458) & ((x-M(:,2)).^2) == min( (x-M(:,2)).^2));

idx =
     4