How to Delete Rectangles with Loops

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Hello,
I am hoping that someone will help me with a problem I am having. I am trying to make a for loop in order to remove a number of given rectangles. However, I have notice that when I run the code and debug it, the deletion is not shown on the graph. I am not sure how to approach this. Even if this may be a simple problem, I would appreciate any input on this situation.
The Code:
axis([0 20 0 5])
rectangle('Position',[0,1,1,1])
rectangle('Position',[1,1,1,1])
rectangle('Position',[2,1,1,1])
rectangle('Position',[3,1,1,1])
rectangle('Position',[4,1,1,1])
rectangle('Position',[5,1,1,1])
rectangle('Position',[6,1,1,1])
rectangle('Position',[7,1,1,1])
rectangle('Position',[8,1,1,1])
rectangle('Position',[9,1,1,1])
rectangle('Position',[10,1,1,1])
rectangle('Position',[11,1,1,1])
rectangle('Position',[12,1,1,1])
rectangle('Position',[13,1,1,1])
rectangle('Position',[14,1,1,1])
rectangle('Position',[15,1,1,1])
x=15;
for i=1:10
h=rectangle('Position',[x,1,1,1])
H=findobj(h)
delete(h)
x=x-1;
M(i)=getframe
end
movie(M)
Thank you in advance.

Accepted Answer

Stephen23
Stephen23 on 18 Jul 2016
Edited: Stephen23 on 18 Jul 2016
You are drawing every rectangle twice: once hardcoded before the loop, and once inside the loop. This means deleting one of them has no effect because the other is still visible. Try this:
axis([0,20,0,5])
V = 1:15;
for k = V
hnd = rectangle('Position',[k,1,1,1]);
M(k)=getframe;
delete(hnd)
end
movie(M)
  5 Comments
Salvador Montes
Salvador Montes on 18 Jul 2016
Edited: Salvador Montes on 18 Jul 2016
Hello Image Analyst,
I have tried checking my units on the rectangle but unfortunately I get the error message that there are no units for the rectangle class. I am not sure if this is common when using 'rectangle'.
Allow me then to ask you what is your suggestion on this situation?
Image Analyst
Image Analyst on 18 Jul 2016
No, it would be the 'units' property of the axes that you're drawing the rectangles on.

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