Compare column vector to matrix
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Hello,
I'm trying to find the first element and its index into a 73X615 matrix, where each value should be less or equal to a value in 73X1 column vector. So let's say that the matrix is
B = -5 + (5+1)*rand(73,615);
and the vector is
A = -5 + (5+1)*rand(73,1)
My intention is to extract a columns vectors [C, iC], where each value of C is the first value in B that is less or equal than the value in A at the corresponding row, and iC is the index of that value.
My apologies if the question seems a bit contrived, but I'm new to Matlab and I didn't know how to formulate it more clearly.
I hope you can help me with this issue, before hand, many thanks.
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Accepted Answer
Azzi Abdelmalek
on 5 Aug 2016
Edited: Azzi Abdelmalek
on 5 Aug 2016
B = -5 + (5+1)*rand(73,615)
A = -5 + (5+1)*rand(73,1)
id=bsxfun(@le,B,A)
for k=1:size(id,1)
ii=find(id(k,:),1)
out(k,1:2)=[B(k,ii) ii]
end
Incase there are empty indices
B = -5 + (5+1)*rand(73,615)
A = -5 + (5+1)*rand(73,1)
id=bsxfun(@le,B,A)
kk=0
for k=1:size(id,1)
ii=find(id(k,:),1)
if ~isempty(ii)
kk=kk+1
out(kk,1:2)=[B(k,ii) ii]
end
end
out
7 Comments
Azzi Abdelmalek
on 5 Aug 2016
Simon, this is not how it works in this forum, when an answer satisfies your need, you have to mark the answer as accepted. You can also ask for some explanations related to your question, if it's not you have to post another question.
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