how to convert a decimal number within (0, 255) to a 8-bit binary number?

Assume a decimal number 100, it should be converted to 01100100 rather than 01100100 by dec2bin.m.

Is there any efficient way to do that, except bitget(100,[8:-1:1]) that seems a little slow in computation?

Answer 1

[Walter Roberson]

Repeat:

if the current value is odd, emit a 1, otherwise emit a 0
replace the current value with the current value divided by 2, taking the floor() rather than permitting rounding (caution: uint8 rounds)
if the new current value is 0, stop, otherwise repeat