I have a matrix A of order 3 X 7 and C is a matrix made

I have a matrix A of order 3 X 7 and C is a matrix made of first , fourth and seventh columns of A I Need to find a matrix B of order 7 X 3 such that AB=C

A =

    1.0000    3.0000    5.0000    7.0000    9.0000   11.0000   13.0000   15.0000
    2.5000    2.0000    1.5000    1.0000    0.5000         0   -0.5000   -1.0000
    0.2500    0.5000    1.0000    2.0000    4.0000    8.0000   16.0000   32.0000

C= 1.0000    7.0000   13.0000
    2.5000    1.0000   -0.5000
    0.2500    2.0000   16.0000

Answer 1

[Moe_2015]

 B=A\C

B =

    1.0000    0.3445   -0.0766
         0         0         0
         0         0         0
         0         0         0
         0         0         0
    0.0000    0.7943    0.7679
         0         0         0
   -0.0000   -0.1388    0.3086

>> A*B

ans =

    1.0000    7.0000   13.0000
    2.5000    1.0000   -0.5000
    0.2500    2.0000   16.0000

Answer 2

[Changoleon]

>> a = [ 1 3 5 7 9 11 13 15; 2.5 2 1.5 1 0.5 0 -0.5 .1; 0.25 0.5 1 2 4 8 16 32];

>> c = [ 1 7 13; 2.5 1 -0.5; 0.25 2 16];

>> b = 1./(a') * c;

>> b

b =

    3.0000   15.4000   76.8000
    2.0833    6.8333   36.0833
    2.1167    4.0667   18.2667
    2.7679    3.0000    9.3571
    5.1736    3.2778    4.4444
       Inf       Inf      -Inf
   -4.9075   -1.3365    3.0000
   25.0745   10.5292   -3.6333

>>

[Srikar Kalivarapu]

A*B doesnt give me C again