Problem in plotting the matrix over an image.
Show older comments
I am required to read an image,find out its rgb channels and then in those channels separately,mark the pixels whose value exceeds above a certain threshold value.I wrote the following code for marking the pixels but they are not getting marked and I am getting the error that it exceeds matrix dimensions.What am I doing wrong in the code? Below is the code-
img=imread('test.jpg');
imshow(img)
redchannel=img(:,:,1);
greenchannel=img(:,:,2);
bluechannel=img(:,:,3);
rs=zeros(size(redchannel));
r1=cat(3,redchannel,rs,rs);
figure
imshow(r1)
gs=zeros(size(greenchannel));
g1=cat(3,gs,greenchannel,gs);
figure
imshow(g1)
bs=zeros(size(bluechannel));
b1=cat(3,bs,bs,bluechannel);
figure
imshow(b1)
[r,c,~]=size(img);
indx=zeros(r,c);
for i=1:r
for j=1:c
if ((redchannel(i,j))>=180)
indx(i,j)=1;
end
end
end
for i=1:r
for j=1:c
imshow(r1)
hold on
plot(indx(:,1),indx(:,2),'b*');
hold off
end
end
5 Comments
KSSV
on 16 Nov 2016
Your code is taking hell lot of time: Use below modified code.
img=imread('Prachi Sharma image');
imshow(img)
%
redchannel=img(:,:,1);
greenchannel=img(:,:,2);
bluechannel=img(:,:,3);
%
rs=zeros(size(redchannel));
r1=cat(3,redchannel,rs,rs);
figure
imshow(r1)
%
gs=zeros(size(greenchannel));
g1=cat(3,gs,greenchannel,gs);
figure
imshow(g1)
%
bs=zeros(size(bluechannel));
b1=cat(3,bs,bs,bluechannel);
figure
imshow(b1)
%
[r,c,~]=size(img);
indx=zeros(r,c);
indx(redchannel>=180) = 1 ;
% for i=1:r
% for j=1:c
% if ((redchannel(i,j))>=180)
% indx(i,j)=1;
% end
% end
% end
for i=1:r
for j=1:c
imshow(r1)
hold on
plot(indx(:,1),indx(:,2),'b*');
drawnow
hold off
end
end
Can you tell me what you are trying to do here? Why loop needed here?
for i=1:r
for j=1:c
imshow(r1)
hold on
plot(indx(:,1),indx(:,2),'b*');
drawnow
hold off
end
end
Prachi Sharma
on 16 Nov 2016
Important note:
redchannel = img(:,:,1);
rs = zeros(size(redchannel));
r1 = cat(3, redchannel, rs, rs);
That's very dangerous because there's no class specified in the zeros call. rs is always going to be of class double, whereas redchannel may be of a different class (if it comes from a jpeg image, it'll be uint8). You're then combining matrices of different classes which may not produce the result you expect.
Much safer would be:
redchannel = img(:,:,1);
rs = zeros(size(redchannel), class(redchannel)); %make sure rs is of the same class as redchannel
r1 = cat(3, redchannel, rs, rs);
or even better:
r1 = img; %r1 is same class as img
r1(:, :, [2 3]) = 0; %note that the double 0 gets converted to 0 of the class of r1
Image Analyst
on 16 Nov 2016
Do you want to change the actual pixel values, like make them red or something? OR do you want to leave the pixel values the same and just change how they are displayed, like use a colormap where those pixels are red, or use a binary overlay ?
Prachi Sharma
on 17 Nov 2016
Answers (3)
KSSV
on 16 Nov 2016
clc; clear all ;
img=imread('Prachi Sharma image');
imshow(img)
%
redchannel=img(:,:,1);
greenchannel=img(:,:,2);
bluechannel=img(:,:,3);
%
rs=zeros(size(redchannel));
r1=cat(3,redchannel,rs,rs);
figure
imshow(r1)
%
gs=zeros(size(greenchannel));
g1=cat(3,gs,greenchannel,gs);
figure
imshow(g1)
%
bs=zeros(size(bluechannel));
b1=cat(3,bs,bs,bluechannel);
figure
imshow(b1)
%
[r,c,~]=size(img);
indx=NaN(r,c);
indx(redchannel>=180) = 1 ;
%
imshow(r1) ;
x = 1:c ;
y = 1:r ;
[X,Y] = meshgrid(x,y) ;
hold on
plot3(X,Y,indx,'*b') ;
3 Comments
Prachi Sharma
on 16 Nov 2016
Edited: Prachi Sharma
on 16 Nov 2016
KSSV
on 16 Nov 2016
You try it out...this is the way the matrix size of x,y making equal to indx. Do consider the Guillaume comments.
Prachi Sharma
on 16 Nov 2016
find will return the locations of all the values above the threshold, there's no need for a loop
img = imread('test.jpg');
redchannel = img(:, :, 1);
[row, column] = find(redchannel > 180); %no need for loop
redimage = img; redimage(:, :, [2 3]) = 0;
figure;
imshow(redimage);
hold on;
plot(column, row, 'b*'); %column, row <=> x, y. Stupid matlab can't decide on a single coordinate system!
and do the same for green and blue.
edit: also see my comment to the question about using zeros with no class specified.
11 Comments
Prachi Sharma
on 16 Nov 2016
Edited: Prachi Sharma
on 16 Nov 2016
Guillaume
on 16 Nov 2016
redimage(:, :, [2 3]) selects all the rows, all the columns and only index 2 and 3 of the third dimension. index 2 is the green channel, and index 3 is the blue channel. In effect, this set all the green and blue value to 0. If you wanted to keep just the green channel, then:
img(:, :, [1 3]) = 0; %1and 3 is red and blue respectively
find use the normal matlab convention where the first value it returns is the row of the matrix, and the second value is the column of the matrix. plot and a few other functions (most of of the image processing toolbox, as well as gradient, meshgrid and maybe more) use a different coordinate system (x, y) where x corresponds to the columns, and y to the rows. This is matches the way you normally references coordinates outside matlab but as a result you end up with two different coordinates system where one is swapped compared to the other.
Personally, I think it's stupid (hence my comment in the code). In my opinion it would be much better to be internally consistent but that's what it is: plot uses (x, y) coordinates which is (column, row), find uses (row, column) which is (y, x).
Image Analyst
on 16 Nov 2016
MATLAB is not the only one. Have you ever noticed the two conventions for numeric keypads - how your keyboard and phone are upside down with respect to each other? But yes, x,y and row,column trips up lots of people.
Prachi Sharma
on 17 Nov 2016
Prachi Sharma
on 17 Nov 2016
No, it doesn't and it can't. The code I've written does exactly and only this:
- find the locations of pixels whose red pixels are above the threshold
- creates a duplicate of the image where only the red channel is active
- displays the image
- overlays on the display blue stars at the locations found in the 1st step.
At no point does it alter the value of pixels above any threshold.
Prachi Sharma
on 17 Nov 2016
KSSV
on 17 Nov 2016
As suggested by Guillaume in other discussion.
[Y,X,V] = redchannel>=180 ;
Follow the same for other channels.
Prachi Sharma
on 17 Nov 2016
KSSV
on 17 Nov 2016
Dear friend then type it..what is stopping you?
Prachi Sharma
on 17 Nov 2016
Edited: Prachi Sharma
on 17 Nov 2016
Image Analyst
on 17 Nov 2016
Try something like this:
% Extract the individual red, green, and blue color channels.
redChannel = rgbImage(:, :, 1);
greenChannel = rgbImage(:, :, 2);
blueChannel = rgbImage(:, :, 3);
% Make mask where ANY of the color channels is saturated.
saturatedPixels = redChannel == 255 | greenChannel == 255 | blueChannel == 255;
% Make red channel 255, and other color channels 0 where there is saturation
redChannel(saturatedPixels) = 255;
greenChannel(saturatedPixels) = 0;
blueChannel(saturatedPixels) = 0;
% Recombine separate color channels into a single, true color RGB image.
rgbImage = cat(3, redChannel, greenChannel, blueChannel);
imshow(rgbImage);
Now your RGB image will be pure red wherever ANY pixel of ANY color channel is saturated (value of 255). For an image in the range 0-1, use 1 instead of 255. For a uint16 image, use 65535 instead of 255.
Categories
Find more on White in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!