The Code Runs Too Long, Should I Abort It?

I run this code and I think it runs too long. Any solution?

c6 and c3 is matrix with 3300x2200 grids.

if true
e=0.06+c6;
f=c3;
[m,n]=size(f);
for i=1:m;
  for j=1:n;
      if f(i,j)>e;
         t(i,j) = 1;
      else
         t(i,j) = 0;
      end
  end
end
end

Answer 1

[Adam]

Can't you just replace the whole thing with:

t = c3 > e;

or

t = double( c3 > e );

if you want the 0s and 1s as doubles rather than logicals?

doc vectorization

gives an introduction to this very powerful alternative to nested for loops which is almost always noticeably faster too.

[Ashvin Hamzah Driwantara]

u mean like this?

if true
e=0.06+c6;
f=c3>e;
[m,n]=size(f);
for i=1:m;
  for j=1:n;
      if f(i,j)==1;
         t(i,j) = 1;
      else
         t(i,j) = NaN;
      end
  end
end
end

[Adam]

No, I mean just literally replace everything after

e=0.06+c6;

with that one line:

t = c3 > e;