# minimum value is selected always from last iteration

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summyia qamar on 16 Dec 2016
Commented: summyia qamar on 19 Dec 2016
part_machine=[1 0 0 1 0 1 1;
0 1 1 1 0 0 1;
1 0 0 1 1 0 0;
1 0 0 0 1 0 1;
1 1 0 0 0 1 0;
0 1 0 0 0 1 1];
demand=[600;550;620;500;590;600];
numIterations=3;
for k=1:numIterations
rand_cell_assigntomachines=randi([0,1],7,3);
Part_cell=part_machine*rand_cell_assigntomachines;
Part_cell(Part_cell>=1)=1;
no_of_movements=sum(Part_cell,2)-1;
movement_cost=sum(bsxfun(@times,no_of_movements,demand))
end
minval=min(movement_cost)
the result is
movement_cost =
5110
movement_cost =
6920
movement_cost =
6300
minval =
6300
but in 3 iterations, 6300 is not minimum value.. I checked it and the value which is always picked as min is from the last iteration.. why is this so?

Walter Roberson on 16 Dec 2016
Assign to movement_cost(k) instead of overwriting all of movement_cost
summyia qamar on 19 Dec 2016
I'm running this code.
part_machine=[1 0 0 1 0 1 1
0 1 1 1 0 0 1
1 0 0 1 1 0 0
1 0 0 0 1 0 1
1 1 0 0 0 1 0
0 1 0 0 0 1 1];
demand=[600;550;620;500;590;600];
numIterations=100;
for k=1:numIterations
rand_cell=randi([0,1],7,3);
if all(sum(rand_cell,2)==1);
Part_cell(k)=part_machine*rand_cell;
end
Part_cell(Part_cell>=1)=1
no_of_movements=sum(Part_cell,2)-1;
movement_cost(k)=sum(bsxfun(@times,no_of_movements,demand));
end
minval=min(movement_cost);
[rand_cell minval(ones(7,1))]
the idea behind this code is * generate rand_cell * select that rand_cell in which sum of rows is 1 * multiply Part_machine matrix with that rand_cell * then apply the other functions on part_machine matrix * then at the end select the minval from all iterations * result is displayed with that rand_cell matrix which has generated the minimum value
now the result I'm getting is like this
ans =
1 0 1 6920
1 0 0 6920
0 1 0 6920
1 1 0 6920
1 1 1 6920
1 1 1 6920
1 0 1 6920
it is not the rand_cell matrix according to condition
all(sum(rand_cell,2)==1)
where is the problem?