Using genetic algorithm (ga) function for integer and linear inequality constrained optimization. Candidate solutions are violating the inequality constraints
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I am using the ga() function in the Global Optimisation Toolbox. The problem is constrained by a linear inequality and all the optimisation variables must be integers:
problem.Aineq=[1 1 1 1 1 1];
problem.bineq = 12;
problem.intcon=[1 2 3 4 5 6];
However by looking at the population at various points through the evolution I can see that there are some candidate solutions being generated that violate the inequality constraint.
E.g. A candidate_solution might be: [3 2 2 2 2 2]
I am concerned that the ga() function is "wasting" computing time by evaluating the fitness of solutions that are outside the constrained solution space. Can anyone confirm if this is the case?
From reading the MATLAB documentation for ga() and constrained optimisation it states: "All the linear constraints and bounds are satisfied throughout the optimization." https://uk.mathworks.com/help/gads/examples/constrained-minimization-using-the-genetic-algorithm.html.
Am I misusing ga() if it is violating the constraints?
Thanks
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Accepted Answer
Alan Weiss
on 17 Jan 2017
Sorry about that, this is a documentation problem. Thank you for reporting the problem. I will fix the documentation soon.
According to a developer, when there are integer constraints, ga strictly enforces bound constraints, but no longer strictly enforces linear constraints. The linear constraints become part of the penalty function that attempts to keep things feasible, but, indeed, the population can be infeasible.
As for what you can do about it, I suppose that you could give a large fitness value for infeasible members as has already been suggested. Or, since your linear constraint is particularly simple, you could write your own mutation, crossover, and creation functions that ensure both an integer-feasible and linear-feasible population, and dispense with the built-in ga version. You see, it is not so easy to satisfy general linear and integer constraints, but your constraint is not at all hard to satisfy.
Again, sorry for the erroneous information in the doc.
Alan Weiss
MATLAB mathematical toolbox documentation
3 Comments
Doug Rank
on 5 Jul 2017
I just found this post and wanted to iterate that the documentation appears to still be inaccurate with regards to this issue. It has caused some confusion and uncertainty the past couple months.
Alan Weiss
on 6 Jul 2017
It is unfortunate that the documentation deadline for the March software release was before the end of January, so my documentation update did not appear in R2017a. It will in R2017b, I assume.
Alan Weiss
MATLAB mathematical toolbox documentation
More Answers (1)
Matt J
on 17 Jan 2017
Edited: Matt J
on 17 Jan 2017
You can specify the mutation function in the Mutation function (MutationFcn) field in the Mutation options pane. Do not use with integer problems. You can choose from the following functions:
I guess the various options available for mutation don't apply when integer constraints are in play.
The existence on unfeasible candidates in the population is not necessarily a problem for me, IF they are not passed to the fitness function for evaluation. Can anyone tell me if this is the case, or a possible fix.
If you are worried about efficiency, I would simply insert a constraint check into the fitness function. In other words, test whether the input satisfies the linear constraints at the very beginning of the fitness function routine and abort all subsequent computations (returning a fitness value of Inf) if it does not. If this slows down execution significantly, it's a pretty good sign that ga is already doing this for you.
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