a(a(a>3)<10) = OK ; a(a>3 && a<10) = wrong!, the correct way?
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a=[1 2 3 4 11 33]; I want to get the number in a from 4-9; a(a(a>3)<10) is right; a(a>3 && a<10) is wrong -- is there other correct way to make this ?
Alexandra Harkai on 27 Feb 2017
If you want to get only values between 3 and 10 (excluding the endpoints), the correct way would be:
a(a>3 & a<10)
(Not exactly sure what you meant by 'OK' but a(a(a>3)<10) definitely gives some unexpected results.)
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