Flipping y-axis of findpeaks-plot
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    Nils Norlander
 on 9 Mar 2017
  
    
    
    
    
    Commented: Greg Dionne
    
 on 15 Mar 2017
            Hi!
To find minima-values of an array I multiplied my array with -1 and used findpeaks. To graphically show the minimas I want to reverse the findpeaks-plot but can't figure out how. Any suggestions?
E_bat3 = E_bat2.*(-1);
findpeaks(E_bat3(winter_hours)) %Graph I want to flip.
Thanks!
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Accepted Answer
  Star Strider
      
      
 on 9 Mar 2017
        You may be making this too difficult.
Example —
a = linspace(0, 4*pi);
y = sin(a);
[pks,pkloc] = findpeaks( y,a);                          % Maxima
[vls,vlloc] = findpeaks(-y,a);                          % Minima
figure(1)
plot(a, y, '-b')
hold on
plot(pkloc, pks, '^r', 'MarkerFaceColor','r')
plot(vlloc, -vls, 'vg', 'MarkerFaceColor','g')
hold off
grid
axis([xlim    -1.1  1.1])
legend('Data', 'Peaks', 'Valleys')
Note that to plot the valleys (‘vls’) or minima correctly, simply negate them in the plot call. So to find them, use:
[vls,vlloc] = findpeaks(-y,a);                          % Minima
and to plot them or use them in other calculations correctly, negate them again to restore their correct values:
plot(vlloc, -vls, 'vg', 'MarkerFaceColor','g')
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More Answers (2)
  Adam
      
      
 on 9 Mar 2017
        
      Edited: Adam
      
      
 on 9 Mar 2017
  
      Don't you just want to negate the peak amplitude results rather than flip?
2 Comments
  Adam
      
      
 on 9 Mar 2017
				But if they are minima then they will be larger as an absolute value than those around them so how can you display them still as minima if you plot the result as positive only?
I guess if you really want to do that then you need to subtract from whatever the largest absolute value in the results is.
  Greg Dionne
    
 on 9 Mar 2017
        
      Edited: Greg Dionne
    
 on 9 Mar 2017
  
      I think Star Strider's answer is the right approach, but if you prefer the graphical 'look and feel' of the FINDPEAKS plot, then try this:
load mtlb
findpeaks(mtlb,Fs,'MinPeakProminence',1);
figure
findpeaks(-mtlb,Fs,'MinPeakProminence',1);
set(gca,'YDir','reverse');
set(findobj(gca,'Tag','Peak'),'Marker','^');
set(gca,'YTickLabel',cellfun(@(x)num2str(-str2num(x)),get(gca,'YTickLabel'),'UniformOutput',false))
2 Comments
  Greg Dionne
    
 on 15 Mar 2017
				Yes, that should work. FINDPEAKS expects vector input for Y. So in your case you could do findpeaks(-y, a) just like you did before, but then do the graphics commands above. I think they'll work no matter what input you have (so long as you actually have peaks). Otherwise, finding the 'peak' tag will fail because no peaks will actually be plotted.
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