Rehsaping Data Table to new format

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Matt
Matt on 7 Apr 2017
Answered: Matt on 10 Apr 2017
Hi, I have a data table that exists like:
[date] [field] [data]
1/1/2017 A 1
1/2/2017 A 2
1/3/2017 A 3
1/1/2017 B 3
1/2/2017 B 2
1/3/2017 B 1
1/1/2017 C 4
1/2/2017 C 5
1/3/2017 C 6
and i want to reshape the data to be like this:
[Date] [A] [B] [C]
1/1/2017 1 3 4
1/2/2017 2 2 5
1/3/2017 3 1 6
so that each unique value in fields becomes a new field name in the new table.
I saw this conversion done in a tutorial the other day, but cant recall how it was done at all, thanks for any input in advance!
Matt

Accepted Answer

Peter Perkins
Peter Perkins on 7 Apr 2017
I think you are looking for unstack:
>> t = cell2table( ...
{'1/1/2017', 'A', 1; ...
'1/2/2017', 'A', 2; ...
'1/3/2017', 'A', 3; ...
'1/1/2017', 'B', 3; ...
'1/2/2017', 'B', 2; ...
'1/3/2017', 'B', 1; ...
'1/1/2017', 'C', 4; ...
'1/2/2017', 'C', 5; ...
'1/3/2017', 'C', 6},'VariableNames',{'date' 'field' 'data'});
>> t.date = datetime(t.date,'InputFormat','MM/dd/yyy');
>> t.field = categorical(t.field)
t =
9×3 table
date field data
___________ _____ ____
01-Jan-2017 A 1
02-Jan-2017 A 2
03-Jan-2017 A 3
01-Jan-2017 B 3
02-Jan-2017 B 2
03-Jan-2017 B 1
01-Jan-2017 C 4
02-Jan-2017 C 5
03-Jan-2017 C 6
>> t2 = unstack(t,'data','field')
t2 =
3×4 table
date A B C
___________ _ _ _
01-Jan-2017 1 3 4
02-Jan-2017 2 2 5
03-Jan-2017 3 1 6

More Answers (2)

Steven Lord
Steven Lord on 7 Apr 2017
If your data is stored in a table or timetable, use unstack. The first example on that documentation page is pretty close to the exact scenario you gave, so it should be easy to adapt for your needs.

Matt
Matt on 10 Apr 2017
Both answer the question and accomplish what i was looking to do, thanks very much!

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