How to display images from a cell array?

I have 5 images in a cell array 'imageshares' and I want to display them individually.

    figure
    image(imageshares{i}));

I used the above code and obviously this didn't work. How do I display the images?

[Stephen23]

"I used the above code and obviously this didn't work"

Not much is obvious. Did you out that code in a loop of some kind, or is that the entirety of the code? What were you expecting, and what actually occurred?

[fiona rozario]

I got the following error and a blank figure window popped up:

Subscript indices must either be real positive integers or logicals.

Error in nsharestest (line 39)

image(imageshares{i});

I was expecting 5 windows to show me 5 images. It is in a for i=1:N loop.

[Matthew Eicholtz]

It would be helpful to see more of your code so we can properly diagnose the problem.

[fiona rozario]

 f=imread('test2.jpg');
 red=f(:,:,1);
 green=f(:,:,2);
 blue=f(:,:,3);

 [r,c,d]=size(f);

 shred=zeros(r,c);
 shgreen=zeros(r,c);
 shblue=zeros(r,c);
 image=zeros(r,c);

 N = input('Number of pieces to break into ');
 rowgroups = diff( round(linspace(0,r,N+1)));

 rshares = mat2cell(red, rowgroups, size(red,2));
 gshares = mat2cell(green, rowgroups, size(green,2));
 bshares = mat2cell(blue, rowgroups, size(blue,2));

 imageshares=mat2cell(image, rowgroups, size(image,2));

 shredshares = mat2cell(shred, rowgroups, size(shred,2));
 shgreenshares = mat2cell(shgreen, rowgroups, size(shgreen,2));
 shblueshares = mat2cell(shblue, rowgroups, size(shblue,2));

 for i=1:N
    imageshares{i}=cat(3,rshares{i},gshares{i},bshares{i});
    figure
    image(imageshares{i});
  end

Answer 1

[Star Strider]

The subscript error is puzzling if ‘i=1:N’. One option is to change the loop counter variable to ‘k’ instead, since a few versions back, ‘i’ could default to the imaginary operator.

The imshow function could be a preferable option (with the index variable change):

figure
imshow(imageshares{k})

This is a guess on my part. If I guessed wrong, I will delete this Answer.

[fiona rozario]

I tried this but still got the same error.

Answer 2

[Image Analyst]

image is a built in function. Thus, this makes no sense:

imageshares=mat2cell(image, rowgroups, size(image,2));

and I don't know what you're doing with all that "shares" stuff. You read in one image, which has 3 color channels, so exactly what 5 images are you expecting to see?

[fiona rozario]

I entered the value of N as 5, which is the number of parts the matrix needs to be divided into. I need to divide the RGB components into parts or shares and then combine the individual components to form 5 images.

I changed the 'image' variable name and still got the same error.

[Image Analyst]

To split up an image into tiles: see the FAQ