how to extract strings between two newline characters using regexp
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I have a string:
S = sprintf('\n1 2\n3 4\n')
And I want to extract '1 2' into a cell and '3 4' into a cell, using the following code:
a=regexp(S, '\n\d+[^\n]+\n','match')
But '3 4' was not extracted.
Did I do something wrong?
Accepted Answer
More Answers (2)
Sayam Ganguly
on 12 Jul 2017
From your question I understand that you have a string '\n1 2\n3 4\n' and you want to extract '1 2' and '3 4' into a 1*2 cell array. I would like to suggest a different regexp that should help you achieve your workflow.
a=regexp(S, '.*','match','dotexceptnewline')
Here '.*' automatically considers all the characters but because of the 'dotexceptnewline', the '/n' characters are not considered and you get a 1*2 cell array split with your desired result. In case of your approach the entire pattern was getting matched only once and was not getting repeated.
4 Comments
Li Xue
on 13 Jul 2017
Walter Roberson
on 13 Jul 2017
perl extended regular expressions can get quite complicated !!!
Walter Roberson
on 13 Jul 2017
I programmed in perl for a few years. The rules are not easy to remember. There are multiple books explaining perl regular expressions. For example O'Reilly's "Mastering Regular Expressions" http://shop.oreilly.com/product/9780596528126.do which is over 500 pages.
Most perl regular expression authors make mistakes even on comparatively simple tasks such as matching the valid floating point numbers. Hardly anyone gets right tasks such as balancing brackets (a task which is not possible with true regular expressions, and not possible with perl basic regular expressions, requiring perl extended regular expressions.)
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