I have 3D matrix A=50x60x180 and I want subtract B=50x60 to get same size C=50x50x180? Can anybody use for loop to do this operation?

2 Comments

C = zeros(50,60,180);
for i = 1:180
C(:,:,i) = A(:,:,i) - B;
end
Is this what you mean?
?
size of the C -> [50x 50 x180]? Maybe - [50x 60 x180]

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 Accepted Answer

C = A - B;
or
C = bsxfun(@minus,A,B);

2 Comments

The first of those works in R2016b or later but not in earlier versions.
Walter! I am agree with you!

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