How to separate element in row with different length?

I have a 3168×1 cell array matrix like this:

 a =  
         .
         .
         . 
    [ 9611013]
    [12811019]
    [ 3211001]
    [ 6411007]
    [ 9611013]
    [12811019]
    [16011025]
    [ 3211001]
    [ 6411007]
    [ 9611013]
    [12811019]
    [16011025]
    [ 3211001]
    [ 6411007]
    [ 9611013]
    [12811019]
    [16011025]
         .
         .
         .

I want to separate those number so i get three matrices like this

         .
         .
         . 
    [ 96] [1] [1013]
    [128] [1] [1019]
    [ 32] [1] [1001]
    [ 64] [1] [1007]
    [ 96] [1] [1013]
    [128] [1] [1019]
    [160] [1] [1025]
    [ 32] [1] [1001]
    [ 64] [1] [1007]
    [ 96] [1] [1013]
    [128] [1] [1019]
    [160] [1] [1025]
    [ 32] [1] [1001]
    [ 64] [1] [1007]
    [ 96] [1] [1013]
    [128] [1] [1019]
    [160] [1] [1025]
         .
         .
         .

I have tried

a1 = a(:,(1:5))

but i keep getting error: Index exceeds matrix dimensions. Please help me to fix this. Thank you in advance!

Answer 1

[Stephen23]

Two lines, no loop:

>> a = {9611013;12811019;3211001;6411007;9611013;12811019;16011025;3211001;6411007;9611013;12811019;16011025;3211001;6411007;9611013;12811019;16011025};
>> c = regexp(sprintf('%i_',a{:}),'(\d+)(\d)(\d{4})','tokens');
>> m = str2double(vertcat(c{:}))
m =
     96      1   1013
    128      1   1019
     32      1   1001
     64      1   1007
     96      1   1013
    128      1   1019
    160      1   1025
     32      1   1001
     64      1   1007
     96      1   1013
    128      1   1019
    160      1   1025
     32      1   1001
     64      1   1007
     96      1   1013
    128      1   1019
    160      1   1025

Answer 2

[Robert U]

Hi azurighte,

Taking the data you provided for your task, one possible solution is the following:

 a = { 9611013; 12811019; 3211001; 6411007; 9611013; 12811019; 16011025; 3211001;
       6411007; 9611013; 12811019; 16011025; 3211001; 6411007; 9611013; 12811019;
       16011025 };

 str = cellfun(@num2str,a,'UniformOutput',0);

 % this part might be done more efficiently
 for ik = 1:numel(str)
     a2(ik,:) = [str2num(str{ik}(1:end-5)) str2num(str{ik}(end-4)) str2num(str{ik}(end-3:end))];
 end

Kind regards,

Robert