Solve the initial value problem (xlogx)y'=2y, y(2)=(log2)^2

Answers (1)

syms y(x)
eqn = x*log(x)*diff(y,x)==2*y;
cond = y(2)==log(2)^2;
ysol(x) = dsolve(eqn,cond)
Best wishes
Torsten.

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Asked:

on 25 Oct 2017

Edited:

on 25 Oct 2017

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