For loop index problem

I have 3 variables called all_data_sess1, all_data_sess2 and all_data_sess3 which each contain a 216x8 matrix. When I run the following part of code below, the values for these variables change to just 216 and the matrix is gone, which I don't want. There are 216 rows and I want my for loop to go through each row, which is why I used to loop index 1:length(RT) (I also tried 1:216 but I get the same problem). I ran the whole script line by line and found when it gets to the bit of code below, the value for all_data_sess1 (or 2 or 3) get set to 1, and each time it goes through the for loop, 1 is added every time, hence the end result is all_data_sess1 = 216. How do I make it look at each row and not change/overwrite the matrix assigned to the variable?

 for all_data_sess1 = 1:length(RT) %debugger shows running this line adds 1 to all_data_sess1 each time through the loop, rather than using it as a loop index. 

   if RT <= 2  %Disregarding RTs longer than 2 seconds       Should this cutoff be sooner? RT <= 1.5?

      if performance == 1 %Disregarding incorrect trials    Is this the right way to organise 2 conditions??   if RT <= 2 && if performance == 1?

   sortresultfunction %variables don't change, this isn't working...?

      end

   end

 end

Thanks for any help!

[Roman Müller-Hainbach]

Where is your definition of sortresultfunction?

Answer 1

[KL]

you have to use another variable name as iterator in your for loop

 for k = 1:size(all_data_sess1,1)
   %here use k to index all_data_sess1, for example,
    something = all_data_sess1(k,1);
   ...
   ...
 end