An Edge-Guided Image Interpolation Algorithm via Directional Filtering and Data Fusion
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function A=esintp(I)
%%%%%process A%%%%%%%%%%%%%%%%%%%%%%%%%%%%
[n,m]=size(I);
n=2*n;m=2*m;
A=zeros(n,m);
A(1:2:n,1:2:m)=I;
Ax=A;Ay=A;
f=[-1/16 9/16 9/16 -1/16];
for i=4:2:n-4
for j=4:2:m-4
x=[A(i-3,j-3) A(i-1,j-1) A(i+1,j+1) A(i+3,j+3)];
y=[A(i+3,j-3) A(i+1,j-1) A(i-1,j+1) A(i-3,j+3)];
Ax(i,j)=sum(x.*f);
Ay(i,j)=sum(f.*y);
end
end
for i=4:2:n-4
for j=4:2:m-4
zx=[Ax(i-2,j-2) Ax(i-1,j-1) Ax(i,j) Ax(i+1,j+1) Ax(i+2,j+2)];
zy=[Ay(i+2,j-2) Ay(i+1,j-1) Ay(i,j) Ay(i-1,j+1) Ay(i-2,j+2)];
x=[A(i-1,j-1) A(i+1,j+1) A(i+1,j-1) A(i-1,j+1)];
mx=mean(x);
px=sum((x-mx).^2)/3+0.1;
pzx=sum((zx-mx).^2)/4+0.1;
pzy=sum((zy-mx).^2)/4+0.1;
pv1=pzx-px;pv1=max(0.01,pv1);
pv2=pzy-px;pv2=max(0.01,pv2);
R=[pv1 0;0 pv2];
y=[Ax(i,j) Ay(i,j)]';
H=[1;1];
A(i,j)=mx+px*H'*(H*px*H'+R)^(-1)*(y-H*mx);
end
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Ax=A;Ay=A;
f=[-1/16 0 9/16 1 9/16 0 -1/16];
Ax=conv2(Ax,f);
Ax=Ax(:,4:m+3);
Ay=conv2(Ay,f');
Ay=Ay(4:n+3,:);
c=1.5;
h=[-1 5 5 -1];h=h/sum(h);
for i=5:2:n-5
for j=4:2:m-4
y=[Ax(i-2,j) A(i-1,j) A(i+1,j) Ax(i+2,j)];
my=sum(h.*y);
x=[Ax(i,j-2) Ax(i,j-1) Ax(i,j) Ax(i,j+1) Ax(i,j+2)];
vx=cov(x)+0.1;
vy=c*cov([y my])+0.1;
A(i,j)=(Ax(i,j)*vy+my*vx)/(vx+vy);
end
end
for i=4:2:n-4
for j=5:2:m-5
x=[Ay(i,j-2) A(i,j-1) A(i,j+1) Ay(i,j+2)];
mx=sum(h.*x);
y=[Ay(i-2,j) Ay(i-1,j) Ay(i,j) Ay(i+1,j) Ay(i+2,j)];
vx=c*cov([x mx])+0.1;
vy=cov(y)+0.1;
A(i,j)=(mx*vy+Ay(i,j)*vx)/(vx+vy);
end
end
return;
can anyone explain this code???
2 Comments
Royi Avital
on 7 Jun 2014
Could you point exactly what do you don't understand?
qing zhao
on 13 Nov 2017
this code have something wrong,haven't you found it?
Answers (2)
Image Analyst
on 7 Jun 2014
1 vote
I bet the author could, but probably doesn't want to, or else he or she would have done so by adding comments. I'm not even going to attempt it.
Can someone provide some suggestions about above code.
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