How can I sum anonymous functions?

Dear all, I have a for-loop and every for-loop creates an instance of an anonymous function. In the end I would like to sum all these anonymous functions to one function, which I can then use to evaluate for different t. So far I have the following, which compiles, but gives me an error when trying Hn(0.5). Thanks for your help :)
A= rand(60,200);
X = randn(200,1);
eta = sqrt(0.03)*randn(60,1);
[u, s, v] = svd(A);
[m,~] = size(A);
xi = zeros(m,1);
nu = zeros(m,1);
alpha = zeros(m,1);
Hn = 0;
for i = 1:m
xi(i) = dot(X, v(:,i));
nu(i) = dot(eta, u(:,i));
alpha(i) = xi(i)*(s(i,i)*xi(i)+nu(i));
h = @(t) ((s(i,i)*nu(i)*inv(xi(i))+1)*t-1)/(1-(1-s(i,i)^2)*t)^3;
Hn = @(t) Hn(t)+s(i,i)*alpha(i)*h(t);
end

 Accepted Answer

You need to initialize Hn as an anonymous function as well:
Hn = @(t) 0;

4 Comments

Thank you!! I just forgot about this...
You're welcome. (If this solved your issue, could you mark this as accepted answer? It will give me reputation points and make it easier for others with similar questions to find this answer)
Hello,
I have a similar problem
f = @(x) 0;
for i=1:n
f =(@x) f(x) + c(i) * cos(i*x);
end
where is c is a vector.
It gives an error as: parse error at f: usage might be invalid MATLAB syntax.
What is wrong here?
Thank you in advance
You should put this instead:
f = @(x) 0;
for i=1:n
f =@(x) f(x) + c(i) * cos(i*x);
end

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Asked:

on 31 Oct 2017

Commented:

Rik
on 24 May 2019

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