How can I sum anonymous functions?

4 views (last 30 days)
Judith Wewerka
Judith Wewerka on 31 Oct 2017
Commented: Rik on 24 May 2019
Dear all, I have a for-loop and every for-loop creates an instance of an anonymous function. In the end I would like to sum all these anonymous functions to one function, which I can then use to evaluate for different t. So far I have the following, which compiles, but gives me an error when trying Hn(0.5). Thanks for your help :)
A= rand(60,200);
X = randn(200,1);
eta = sqrt(0.03)*randn(60,1);
[u, s, v] = svd(A);
[m,~] = size(A);
xi = zeros(m,1);
nu = zeros(m,1);
alpha = zeros(m,1);
Hn = 0;
for i = 1:m
xi(i) = dot(X, v(:,i));
nu(i) = dot(eta, u(:,i));
alpha(i) = xi(i)*(s(i,i)*xi(i)+nu(i));
h = @(t) ((s(i,i)*nu(i)*inv(xi(i))+1)*t-1)/(1-(1-s(i,i)^2)*t)^3;
Hn = @(t) Hn(t)+s(i,i)*alpha(i)*h(t);
end

Accepted Answer

Rik
Rik on 31 Oct 2017
You need to initialize Hn as an anonymous function as well:
Hn = @(t) 0;
  4 Comments
Eray Tunç YILMAZ
Eray Tunç YILMAZ on 23 May 2019
Edited: Rik on 24 May 2019
Hello,
I have a similar problem
f = @(x) 0;
for i=1:n
f =(@x) f(x) + c(i) * cos(i*x);
end
where is c is a vector.
It gives an error as: parse error at f: usage might be invalid MATLAB syntax.
What is wrong here?
Thank you in advance
Rik
Rik on 24 May 2019
You should put this instead:
f = @(x) 0;
for i=1:n
f =@(x) f(x) + c(i) * cos(i*x);
end

Sign in to comment.

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!