- Why do you need that?
- See TUTORIAL: Why Variables Should Not Be Named Dynamically (eval)
How to name every row of 100*2500 matrix?
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Md Monirul Islam
on 1 Nov 2017
Commented: Steven Lord
on 27 Nov 2020
currently i am working with a matrix. The dimension of the matrix is 100*2500. I need to assign each row the matrix to a new variable. How i can do this?
6 Comments
Les Beckham
on 1 Nov 2017
But Matlab is designed to allow you to operate on matrices and (more specifically, in this case) subsets of matrices using indexing. That is what per has suggested and, I think, you should try. You don't need to give a separate name like row1 to data(1,:), etc. -- just apply your operation to data(1,:), probably using a loop where the 1 is replaced by the loop index. Then you don't have to code a hundred lines to process row1 through row100.
Please note especially the last bullet in per's last comment.
Accepted Answer
per isakson
on 1 Nov 2017
Edited: per isakson
on 1 Nov 2017
"So all I want is as followings" See TUTORIAL: Why Variables Should Not Be Named Dynamically (eval). However, I guess you need to make your own mistakes to understand that it's a really bad idea.
M = ones( 3, 5 );
for rr = 1 : size(M,1)
variable_name = sprintf( 'row%03d', rr );
assign( variable_name, M(rr,:) );
end
where
function assign( varargin )
switch nargin
case { 2 },
if isvarname( varargin{ 1 } )
Name = varargin{ 1 };
else
error( ['poi: First input argument, ', ...
inputname(1), ' must be a legal name'] ),
end,
Value = varargin{ 2 };
otherwise
error( 'poi: Wrong number of input arguments' ),
end
assignin( 'caller', Name, Value );
end
6 Comments
Muhammad Ammar bin Faizul Azli
on 27 Nov 2020
@Stephen Cobeldick
May i know what would your code be if i were to do the same for column?
Steven Lord
on 27 Nov 2020
With functionality available now, I'd probably use a table array instead of a numeric array.
cities = ["Albuquerque"; "Boston"; "Chicago"; "Dallas"];
dist = array2table(magic(4), 'VariableNames', cities, 'RowNames', cities)
distBC = dist{'Boston', 'Chicago'}
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