How to insert zeros in matrix randomly?

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I have this matrix:
A =
[2, 1, 4, 6, 2;
9, 4, 6, 1, 2;
5, 3, 2, 8, 3;
7, 2, 1, 9, 3;
7, 1, 8, 2, 4]
I try to insert zeros in each row so the matrix should looks like this:
A=[2, 0, 1, 4, 6, 0, 2;
9, 4, 0, 6, 0, 1, 2;
5, 3, 2, 0, 8, 0, 3;
7, 0, 2, 1, 0, 9, 3;
7, 1, 8, 0, 2, 0, 4]
In this case zeros should be inserted in between maximum of 4 digits for all rows. Any idea on how to do it?
  2 Comments
KL
KL on 7 Nov 2017
In this case zeros should be inserted in between maximum of 4 digits for all rows...
What do you mean by that?
Hajem Daham
Hajem Daham on 7 Nov 2017
I mean that zeros should be inserted between only 1 or 2 or 3 or 4 digits for each row as maximum because later I will work on larger matrix.

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Accepted Answer

Guillaume
Guillaume on 7 Nov 2017
A = [2, 1, 4, 6, 2;
9, 4, 6, 1, 2;
5, 3, 2, 8, 3;
7, 2, 1, 9, 3;
7, 1, 8, 2, 4]
zerospercol = randi(4); %up to 4 zeros per column
B = [A, zeros(size(A, 1), zerospercol)]; %append zeros
for row = 1:size(B, 1)
B(row, randperm(size(B, 2))) = B(row, :); %shuffle the row
end
B %display result
  5 Comments
Guillaume
Guillaume on 8 Nov 2017
The code has no restriction on the size of the matrix (other than your computer memory). I've just tried with a 20000 x 1000 matrix and 200 zeros to insert in each row with no problem.
The only reason I could see for the code to error is if you try to put more zeros per row that could possibly fit (i.e. zerosperrow is greater than size(A, 2)+1).
In any case, if you get an error message, always state what that message is.
Hajem Daham
Hajem Daham on 8 Nov 2017
Hi Guillaume, how can I restrict the number of digits(numbers) to maximum of 4 numbers between each two zeros and the same if the four numbers at the start and end of each row. Because the current code sometimes shows more than four numbers between zeros or at start/end of rows, which is not allowed in my case. Thank you.

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