How to calculate moving average
    63 views (last 30 days)
  
       Show older comments
    
Hi,
I have following data:
0.10
0.24
0.30
0.25
0.33
0.35
0.46
0.47
0.48
0.51
0.52
0.53
0.53
0.57
0.58
0.58
0.58
0.59
0.63
0.64
0.66
0.72
I want to take 3-points moving average,
Please help some one
2 Comments
Answers (6)
  Bandar
      
 on 11 Dec 2019
        Take a look this data
file=[1 2 3 4];
movmean(file,3)
which returns 
 1.5000    2.0000    3.0000    3.5000
The filter works as follows:
  1 2  (1+2)/2   = 1.5     when k points at 1
1 2 3  (1+2+3)/3 = 2.0     when k points at 2
2 3 4  (2+3+4)/3 = 3.0     when k points at 3
3 4    (3+4)/2   = 3.5     when k points at 4
Now it is easy to convert it to a logical code or merely use movmean().
3 Comments
  Bandar
      
 on 11 Dec 2019
				A=[1 2 3 4 5 6];
m=ones(1,length(A));
for i=1:length(A)
    if i == 1
        m(i) = (A(i)+A(i+1))/2;
    elseif i == length(A)
        m(i) = (A(i-1)+A(i))/2;
    else
        m(i) = (A(i-1)+A(i)+A(i+1))/3;
    end
end
movmean(A,3)
m
  KL
      
 on 16 Nov 2017
        If you have 2016b or later, use movmean,
 mean_arr = movmean(your_array,3)
0 Comments
  Star Strider
      
      
 on 16 Nov 2017
        1 Comment
  Pallavi Bharati
 on 25 Nov 2020
				How to do centered moving average ...three point centred moving average in matlab without the movmean command as i have matlab 2015
  Sudhakar Rayabarapu
 on 8 Sep 2018
        
      Edited: Sudhakar Rayabarapu
 on 8 Sep 2018
  
      Name your data array A; and keep as a column; then use this command
OutPut = tsmovavg(A, 's', 3, 1)
this will give you the simple moving average
0 Comments
  Pallavi Bharati
 on 24 Nov 2020
        Can anyone help me to compute three point moving average of a 5 year data.I used the filter command but the result are erroneous .I am using MATLAB 2015.And I have a huge data 5 year day wise data and i have to compute three point moving average for each month .
2 Comments
  Pallavi Bharati
 on 24 Nov 2020
				Using looping can be erroneous for so large data please suggest something else
  dpb
      
      
 on 24 Nov 2020
				
      Edited: dpb
      
      
 on 25 Nov 2020
  
			The results aren't "erroneous" (presuming you defined the coefficients correctly), they just depend on how one treats the end conditions...examine the following:
>> x=1:10;
>> movmean(x,3)
ans =
    1.5000    2.0000    3.0000    4.0000    5.0000    6.0000    7.0000    8.0000    9.0000    9.5000
>> filter(ones(1,3)/3,1,x)
ans =
    0.3333    1.0000    2.0000    3.0000    4.0000    5.0000    6.0000    7.0000    8.0000    9.0000
>> conv(x,ones(1,3)/3,'same')
ans =
    1.0000    2.0000    3.0000    4.0000    5.0000    6.0000    7.0000    8.0000    9.0000    6.3333
>> conv(x,ones(1,3)/3,'valid')
ans =
    2.0000    3.0000    4.0000    5.0000    6.0000    7.0000    8.0000    9.0000
>> 
movmean special-cases the end positions to change the divisor to match the number of elements from 2:N on each end; filter and conv do not.
It's up to you to determine the solution you wish to use; none is theoretically any more or less correct than any other; just different assumptions are made.
See Also
Categories
				Find more on Creating and Concatenating Matrices in Help Center and File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!







