How to use quadprog for a function with time dependent constant?
Show older comments
I have an optimization problem where to goal is to minimize the following equation:
f(x) = aβx² - ax + ay + b
where a, b and β are constants and y is a vector of constants. x is the decision variable and is also a vector of the same length as y. To use quadprog to solve this problem, this has to be in the form
f(x) = 1/2 xᵀHx + fᵀx
How do I put my equation in that form when it has the constant in the form of a vector?
Thanks very much!
1 Comment
Matt J
on 17 Dec 2017
It is not clear how your f(x) works out to be scalar-valued. If it is not scalar-valued, quadprog is not applicable and, in fact, it is fundamentally unclear what it means to "minimize" it.
Answers (1)
Don't bother. The minimizing x in your case is given trivially by
xmin=1./(2β)
and the minimum value is then f(1./(2β))
Categories
Find more on Quadratic Programming and Cone Programming in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!