Solving a dde23 problem

This seems simple enough: xdot = -Lx(t-0.1) L is a constant integer 10x10 matrix and x is 10x1 vector.

I am using this code snippet:

x0 = randn(10,1);

sol = dde23(@ddefun,[0.1,0.1,0.1,0.1,0.1,0.1,0.1,0.1,0.1,0.1],x0,[0 5]);

I'm defining ddefun as

function v = ddefun(t,x,Z)

D = diag([2 3 4 4 4 4 4 4 3 2]);

L = D-A; %A is a fixed 10x10 matrix (not written here since it's long)%

v = -L*Z;

end

This gives an error "Not enough input arguments. Error in ddefun (line 5) v = -L*Z"

How do I circumvent this issue and solve for x?

Thanks a lot.

[Torsten]

L is (10x10), Z is (10x10), so L*Z is (10x10). But v must be (10x1).

Best wishes

Torsten.

[Deepayan Bhadra]

Z is 10x1 right? I mean, Z reflects x(t-0.1), that is from x1(t-0.1 to x10(t-0.1). I'm not yet well versed with the DDE syntax. Thoughts?

[Torsten]

Just check it in "ddefun":

[m,n] = size(Z)

Best wishes

Torsten.