switch statement help
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disp('1 for CH4');disp('2 for CO2');disp('3 for N2');
nc =input('components');
if nc > 5
disp('Too Many component')
break
end
for i=1:nc
c(i)=input('c:','s');
switch c(i)
case {'c(i)=1'}
Tc(1,1) = 190;
case {'c(i)=2'}
Tc(1,2) = 120;
case {'c(i)=3'}
Tc(1,3) = 890;
case {'c(i)=4'}
Tc(1,4) = 1210;
case {'c(i)=5'}
Tc(1,5) = 1990;
otherwise
disp('enter the comp')
end
end
% The statement is not working kindly help
1 Comment
Jan
on 4 May 2012
Please do not state only, that this "is not working", but describe the occurring problems with any details. It is much easier to solve a problem than to guess, what the problem is.
Answers (4)
Thomas
on 4 May 2012
try
clear variables
disp('1 for CH4');disp('2 for CO2');disp('3 for N2');
nc =input('components: ');
if nc > 5
disp('Too Many component')
break
end
switch nc
case 1
Tc(1,1) = 190
case 2
Tc(1,2) = 120
case 3
Tc(1,3) = 890
case 4
Tc(1,4) = 1210
case 5
Tc(1,5) = 1990
otherwise
disp('enter the comp')
end
EDIT This might be what you want:
clear variables
disp('1 for CH4');disp('2 for CO2');disp('3 for N2');
nc =input('components: ');
if nc > 5
disp('Too Many component')
break
end
for ii=1:nc
c{ii}=input('c:','s')
switch c{ii}
case '1'
Tc(1,1) = 190
case '2'
Tc(1,2) = 120
case '3'
Tc(1,3) = 890
case '4'
Tc(1,4) = 1210
case '5'
Tc(1,5) = 1990
otherwise
disp('enter the comp')
end
end
4 Comments
Nasir Qazi
on 4 May 2012
Walter Roberson
on 4 May 2012
Then you asked the wrong question.
Thomas
on 4 May 2012
Check Edit..
Nasir Qazi
on 4 May 2012
Walter Roberson
on 4 May 2012
If the user really were entering in the literal string 'c(i)=1' (6 characters) in response to that input() prompt, then those 6 characters would not fit into the c(i) that the input() string is being assigned to. Please keep in mind that a string in MATLAB is an array of characters, not a distinct data type, so multiple array locations need to be allocated to hold a multi-character string.
Expecting the user to know to type in literally
c(i)=4
in response to the "c:" prompt is expecting too much from the user.
1 Comment
Nasir Qazi
on 4 May 2012
Nasir Qazi
on 4 May 2012
7 Comments
Walter Roberson
on 4 May 2012
Probably not. You would not reach case 1 unless c(i)==1 so testing that within the case is redundant.
Nasir Qazi
on 4 May 2012
Walter Roberson
on 4 May 2012
Well if you are happy with it then that is what matters.
Nasir Qazi
on 4 May 2012
Walter Roberson
on 4 May 2012
You are the one who knows what it needs to do. You already said that it runs perfectly. If it solves your problem then style differences are not important at this point.
If you are asking me whether your code solves your problem, then I cannot answer because you have not clearly expressed what you are trying to do (an example with multiple components would help.) When _I_ look at your code, I see parts of it that look unlikely to be right to _me_, but that could just be because I do not understand what you are trying to do.
Nasir Qazi
on 4 May 2012
Walter Roberson
on 4 May 2012
Which 4 would you want to assign to in that case? The first 4? Would the same value be assigned to Tc for each of the 4? In your array Tc(i,:) which one is the component number, and what does the other dimension represent?
Andrei Bobrov
on 4 May 2012
in your case
eg:
c = randi([1 5],10,1);
pt = [[190;120;890;1210;1990],[2;4;6;4;8]];
Tc = pt(c,1);
Pc = pt(c,2);
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