how to compare string array with the names of structure's fields.

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I have a structure with 12 fields and a string array named variables containing 4 values. I want to compare all values in my string arrays with the names of my structure fields, and if the fields' name and the string value were the same, return values of that field as an output. I try strcmp command to compare my string array with the fields' name in a for loop.(for i = 1:numel(variables)) then I use switch and case but I have no idea how to return the field values as an output when the statement is true. (I think I should use getfield command but I don't know how). could you please help me in this regard. thank you.
  1 Comment
Adam
Adam on 2 Jul 2018
You can use dynamic strings to get data out of a struct field e.g.
str = 'SomeStructFieldName';
value = myStruct.( str );

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Accepted Answer

Paolo
Paolo on 2 Jul 2018
S.a = {'First field'};
S.b = {'Second field, entry 1','Second field,entry 2'};
S.c = {1,2,3};
mystring = {'a','game','matlab','c'};
[~,indx] = ismember(fieldnames(S),mystring);
all = arrayfun(@(x) getfield(S,mystring{x}),indx(indx>0),'un',0);
all{:} =
{'First field'}
{[1]} {[2]} {[3]}
  3 Comments
Paolo
Paolo on 3 Jul 2018
T = table(all{:});
T.Properties.VariableNames = mystring(indx(indx>0));
T =
1×2 table
a c
_____________ _________________
'First field' [1] [2] [3]

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More Answers (1)

Stephen23
Stephen23 on 3 Jul 2018
Edited: Stephen23 on 3 Jul 2018
I would use struct2cell to get a cell array, then used basic MATLAB indexing to obtain the "fields" (rows of the cell array) that you want. Using a cell array makes it easy to use cell2table to generate a table from the cell array and the fieldnames:
>> S.a = '1st';
>> S.b = {'2ndOne','2ndTwo'};
>> S.c = 3;
>> F = fieldnames(S);
>> C = struct2cell(S);
>> lookfor = {'a','hello','world','c'};
>> [idx,idy] = ismember(lookfor,F);
>> idz = idy(idx)
>> T = cell2table(C(idz,:),'VariableNames',F(idz))
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